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GenaCL600 [577]
4 years ago
6

The light radiated from the Sun's surface reaches Earth in about 8 minutes. However, the energy of this light was released by fu

sion in the Sun's core about The light radiated from the Sun's surface reaches Earth in about 8 minutes. However, the energy of this light was released by fusion in the Sun's core about several thousand years ago. several hundred thousand years ago. several hundred years ago. 11 years ago. 8 minutes ago.
Physics
1 answer:
timama [110]4 years ago
6 0

Answer:

The light radiated from the Sun's surface reaches Earth in about 8 minutes. However, the energy of this light was released by fusion in the Sun's core about several hundred thousand years ago.

Explanation:

Nucleosynthesis is the fusion of lighter elements into heavier elements. For the Sun the main mechanism of fusion is the proton - proton chain, in which two hydrogen atoms fuse into helium, in the course of the fusion photons are created.

When those photons start their travel from the core to the surface of the star, they will interact with different atoms in the whole way (the main free path).

More precisely, when a photon¹ is absorbed by an electron in an atom of a particular element, the electron will get to a higher state. When it comes back to the ground state, a photon will be emitted again.

The process described above is repeating multiple times for every photon until they reach the Sun surface.    

The whole process can take about several hundred thousand of years.

Key term:

¹Photon: Particle that constitutes light.

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Accomplished silver workers in india can pound silver into incredibly thin sheets, as thin as 3.00 10-7 m (about one-hundredth o
postnew [5]
The density of silver is ρ = 10500 kg/m³ approximately.

Given:
m = 1.70 kg, the mass of silver
t = 3.0 x 10⁻⁷ m, the thickness of the sheet

Let A be the area.
Then, by definition,
m = (t*A)*ρ

Therefore
A = m/(t*ρ)
    = (1.7 kg)/ [(3.0 x 10⁻⁷ m)*(10500 kg/m³)]
    = 539.7 m²

Answer: 539.7 m²

8 0
3 years ago
What happens when two forces act in the same direction?
Sholpan [36]

bigger acceleration......................

7 0
4 years ago
A crane does 62,500 joules of work to lift a boulder a distance of 25.0 meters. How much did the boulder weight
alukav5142 [94]
Work = (force) x (distance)

62,500 joules = (boulder's weight) x (25 meters)

Divide each side by (25 meters) :

Boulder's weight = (62,500 joules) / (25 meters) = <u>2,500 newtons</u>

That's about 562 pounds.
7 0
3 years ago
I WILL GIVE BRAINLIEST IF SOMEONE GETS THIS......
pav-90 [236]

Answer:

Explanation:

a)

Firstly to calculate the total mass of the can before the metal was lowered we need to add the mass of the eureka can and the mass of the water in the can. We don't know the mass of the water but we can easily find if we know the volume of the can. In order to calculate the volume we would have to multiply the area of the cross section by the height. So we do the following.

100cm^{2} x 10cm = 1000cm^{3}

Now in order to find the mass that water has in this case we have to multiply the water's density by the volume, and so we get....

\frac{1g}{cm^{3} } x 1000cm^{3} = 1000g or 1kg

Knowing this, we now can calculate the total mass of the can before the metal was lowered, by adding the mass of the water to the mass of the can. So we get....

1000g + 100g = 1100g or 1.1kg

b)

The volume of the water that over flowed will be equal to the volume of the metal piece (since when we add the metal piece, the metal piece will force out the same volume of water as itself, to understand this more deeply you can read the about "Archimedes principle"). Knowing this we just have to calculate the volume of the metal piece an that will be the answer. So this time in order to find volume we will have to divide the total mass of the metal piece by its density. So we get....

20g ÷ \frac{8g}{cm^{3} } = 2.5 cm^{3}

c)

Now to find out the total mass of the can after the metal piece was lowered we would have to add the mass of the can itself, mass of the water inside the can, and the mass of the metal piece. We know the mass of the can, and the metal piece but we don't know the mass of the water because when we lowered the metal piece some of the water overflowed, and as a result the mass of the water changed. So now we just have to find the mass of the water in the can keeping in mind the fact that 2.5cm^{3} overflowed. So now we the same process as in number a) just with a few adjustments.

\frac{1g}{cm^{3} } x (1000cm^{3} - 2.5cm^{3}) = 997.5g

So now that we know the mass of the water in the can after we added the metal piece we can add all the three masses together (the mass of the can. the mass of the water, and the mass of the metal piece) and get the answer.

100g + 997.5g + 20g = 1117.5g or 1.1175kg

5 0
3 years ago
Suppose you place an object 8 cm in front of a converging lens and the image appears 16 cm on the other side of the lens. What i
Marianna [84]

Answer:

5.33 cm

Explanation:

The lens equation states that:

\frac{1}{f}=\frac{1}{p}+\frac{1}{q}

where

f is the focal length

p is the distance of the object from the lens

q is the distance of the image from the lens

In this problem,

p = 8 cm

q = 16 cm ( the sign is positive since the image is real, which means it is formed on the other side of the lens)

Substituting into the equation,

\frac{1}{f}=\frac{1}{8 cm}+\frac{1}{16 cm}=\frac{3}{16 cm}

f=\frac{16}{3}cm=5.33 cm

3 0
3 years ago
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