Answer:
Almost all skin cancers (approximately 99% of non-melanoma skin cancers and 95% of melanoma) are caused by too much UV radiation from the sun or other sources such as solaria (solarium, sunbeds, and sun lamps).
Explanation:
Skin cancer develops in the cells in the epidermis – the top or outer layer of the skin. UV radiation is made up of UVA and UVB rays which are able to penetrate the skin and cause permanent damage to the cells below:
UVA penetrates deeply into the skin (the dermis) causing genetic damage to cells, photo-ageing (wrinkling, blotchiness etc) and immune-suppression.
UVB penetrates into the epidermis (top layer of the skin) causing damage to the cells. UVB is responsible for sunburn – a significant risk factor for skin cancer, especially melanoma.
If the body is unable to repair this damage the cell can begin to divide and grow in an uncontrolled way. This growth can eventually form a tumor.
UVA and UVB both contribute to sunburn, skin ageing, eye damage and melanoma and other skin cancers.
Answer:
heights of sea level and the space between gas molecules.
Explanation:
Asking that Which factor increases as a result of increasing altitude?
As the height above the sea increases, air density decreases because the molecule of the air will spread out causing air density to decrease. Also, there will be less air pressing down which will lead to a decrease in air pressure.
Therefore, the heights of sea level, and space between gas molecules are the factor that will increase as a result of increasing altitude. Not Air pressure and air density. But the heights of sea level and the space between gas molecules.
Answer:
a)11,71 m/s
b)12.73 m/s
Explanation:
We apply the conservation principle because there is no friction between the hill and the sled:
Total initial energy (Ei) = Total initial energy (Ef), Equation(1)
We define:
K = Kinetic energy = 
U = Potential energy = 
m = mass (kg)
v = velocity (m/s)
h = height (m)
g = gravity acceleration = 
A) hi=7m, hf=0 ,vi=0 , vf=?
Answer: She reaches the base of the hill with speed of 11.22 m/s
B) hi=7 m, vi=5 m/s, hf=0, vf=?
We divide all terms by m
Answer: She will move with a speed of 12.73 m/s when she reaches the base of the hill
