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Sauron [17]
3 years ago
12

Equal volumes of two equimolar solutions of reactants a and b are mixed, and the reaction a+b→c occurs. at the end of 1h, a is 9

0% reacted. how much of a will be left unreacted at the end of 2h if the reaction is: part a first order in a and zero order in b? express your answer in percent using two significant figures, leave the percent sign out of your answer. [a] = 1.0 % submitmy answersgive up correct part b first order in a and first order in b?
Chemistry
1 answer:
SVEN [57.7K]3 years ago
8 0

<span>a)    </span>First order in A and zero order in B

<span>ln [A] = (ln 0.1) (2) + ln Ao = ln 0.01 + ln Ao = ln 0.01 Ao = 1.0%  of A will remain</span>

<span>b)    </span>First order in A and first order in B

<span>1/[A] – 1/[A]0= kt where t+=1 and k=9</span>

[A]/[A]=1/19=0.053=5.3%

<span>c)    </span>Zero order in both A and B

<span>[A]0-[A] = kt</span>

Then at 2 hours [A]=0 All of it has reacted.

 

<span> </span>

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How many molecules are in 0.500 mole of N2O5?
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Use the equation for density :
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Unit: Stoichiometry
Reika [66]

Answer:

1. 2.41 × 1023 formula units

2. 122 L

3. 7.81 L

Explanation:

1. Equation of the reaction: 2 Na(NO3) + Ca(CO3) ---> Na2(CO3) + Ca(NO3)2

Mole ratio of NaNO3 to CaCO3 = 2 : 1

Moles of CaCO3 = mass/molar mass

Mass of CaCO3 = 20 g; molar mass of CaCO3 = 100 g

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0.4 moles of NaNO3 = 0.4 × 6.02 × 10²³ = 2.41 × 1023 formula units

2. Equation of reaction : 2 H2O ----> 2 H2 + O2

Mole ratio of oxygen to water = 1 : 2

At STP contains 6.02 × 10²³ molecules = 1 mole of water

6.58 × 10²⁴ molecules = 6.58 × 10²⁴ molecules × 1 mole of water/ 6.02 × 10²³ molecules = 10.93 moles of water

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5.465 moles of oxygen gas = 5.465 moles × 22.4 L/1 mole = 122 L

3.Equation of reaction: 6 K + N2 ----> 2 K3N

Mole ratio of Nitrogen gas and potassium = 6 : 1

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Mass of potassium = 90.0 g, molar mass of potassium = 39.0 g/mol

Moles of potassium = 90.0 g / 39.0 g/mol = 2.3077moles

Moles of Nitrogen gas = 2.3077 moles / 6 = 0.3846 moles

At STP, 1 mole of nitrogen gas = 22.4 L

0.3486 moles of oxygen gas = 0.3486 moles × 22.4 L/1 mole = 7.81 L

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In the reaction 2Al2O3 → 4Al + 3O2, what is the mole ratio of aluminum to oxygen?
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