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blsea [12.9K]
3 years ago
15

Give the nuclear symbol for the isotope of potassium for which a=40?

Chemistry
2 answers:
KATRIN_1 [288]3 years ago
4 0

<span>nuclear symbol consists of three parts: 1. the symbol of the element; 2. the atomic number of the element;3. the mass of the element. for the above problem, the symbol for potassium is k. it's atomic number is 40. the number of protons is 19. so we denote this in the following nuclear symbol; 40 k 19</span>

Firdavs [7]3 years ago
4 0

The nuclear symbol for potassium is ⁴⁰₁₉K.

FURTHER EXPLANATION

  • The nuclear symbol is typically used to represent isotopes of an atom. Isotopes are variations of atoms of an element. Isotopes have different numbers of neutrons than other forms of the atom.
  • The nuclear symbol has three parts: symbol of the element, the atomic number, and the mass number. The general notation for the nuclear symbol of an element is: ᵃₙX   where a is the mass number and n (or typically z) is the atomic number.
  • The mass number, a, is the total number of protons and neutrons in the nucleus of an atom.
  • The atomic number is the number of protons in the nucleus of a neutral atom.
  • The difference between the mass number and the atomic number is the number of neutrons in the isotope.
  • Another notation used to represent isotopes is the hyphen notation. This notation uses the name of the element, a hyphen followed by the mass number of the isotope. For example, the isotope ¹²₆C can also be represented using the hyphen notation as carbon - 12.

<em>For the nuclear symbol of potassium, it is necessary to find the atomic number of potassium from the periodic table of elements. This number is equal to 19 which means that potassium has 19 protons. The symbol for potassium is K and its mass number as given in the problem is 40. Therefore, the nuclear symbol is </em><em>⁴⁰₁₉K.</em>

<em></em>

<h3>LEARN MORE</h3>
  • Isotopes brainly.com/question/419606
  • Periodic Table brainly.com/question/1446926

<em>Keywords: isotope, nuclear symbol</em>

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A flexible container at an initial volume of 3.10 L contains 9.51 mol of gas. More gas is then added to the container until it r
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Answer:

49.09 moles of gas are added to the container

Explanation:

Step 1: Data given

Initial volume = 3.10 L

Number of moles gas = 9.51 moles

The final volume = 19.1 L

The pressure, temperature remain constant

Step 2: Calculate number of moles gas

V1/n1 = V2/n2

⇒with V1 = the initial volume of the gas = 3.10 L

⇒with n1 = the initial number of moles = 9.51 moles

⇒with V2 = the increased volume = 19.1 L

⇒with n2 = the final number of moles gas

3.10L / 9.51 moles = 19.1 L / n2

n2 = 58.6 moles

The new number of moles is 58.6

Step 3: calculate the number of moles gas added

Δn = 58.6 - 9.51 = 49.09 moles

49.09 moles of gas are added to the container

7 0
3 years ago
What is the mass in grams, if you have 8.42 x 10^18 atoms of Bromine
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Answer:

84.2 grams

Explanation:

you have to multiply 8.42x10^18 to get the answer above

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Which of the following statement is not true?
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Dalton’s Law CalculationA mixture of H₂, N₂ and Ar gases is present in a steel cylinder. The total pressure within the cylinder
Zolol [24]

Answer:

A) The partial presssure of CO₂ is 167 mm Hg

B) The partial presssure of N₂ is 354 mm Hg

C) The partial presssure of Ar is 235 mm Hg

D) The partial presssure of H₂ is 86 mm Hg

Explanation:

Dalton's law of partial pressures is basically expressed by the following statement:

The total pressure of a mixture is equal to the sum of the partial pressures of its components.

So initially we have:

P_{T}= total presure of the system (675 mm Hg).

P_{N_2}= partial pressure of N₂ (354 mm Hg).

P_{Ar}= partial pressure of Ar (235 mm Hg).

Using Dalton's law we can find the partial pressure of H₂:

P_{T}=P_{N_2}+P_{Ar}+P_{H_2}

675 mm Hg=354 mm Hg + 235 mm Hg + P_{H_2}

P_{H_2}= 675 mm Hg - 354 mm Hg - 235 mm Hg

P_{H_2}=86 mm Hg

If CO₂ gas is added to the mixture, at constant temperature, and the volume is the same, the difference between the new total pressure and the previous total pressure is equal to the partial pressure of CO₂.

P_{T}=P_{N_2}+P_{Ar}+P_{H_2}+P_{CO_2}

842 mm Hg= 354 mm Hg + 235 mm Hg + 86 mm Hg + P_{CO_2}

P_{CO_2}= 842 mm Hg - 354 mm Hg - 235 mm Hg - 86 mm Hg

P_{CO_2}= 167 mm Hg

4 0
3 years ago
Phthalates used as plasticizers in rubber and plastic products are believed to act as hormone mimics in humans. The value of ΔHc
jeka94

Answer:

T_f = 25.05°C

Explanation:

Given:

the value of ΔHcomb (heat of combustion) for dimethylphthalate (C10H10O4) is = 4685 kJ/mol.

mass = 0.905g of dimethylphthalate

molar mass = 194.18g dimethylphthalate

number of moles of dimethylphthalate = ???

T_i = 21.5°C

C_{calorimeter} = 6.15 kJ/°C

T_f = ???

since we have our molar mass and mass of dimethylphthalate ;we can determine the number of moles as;

0.905g of dimethylphthalate ×  \frac{1 mole (dimethylphthalate)}{194.184g(dimethylphthalate)}

number of moles of dimethylphthalate = 0.000466 moles

Heat released = moles of dimethylphthalate × heat of combustion

=  0.000466 moles × 4685 kJ

= 21.84 kJ

∴ Heat absorbed by the calorimeter =  C_{calorimeter} (T_f-T_i} )

21.84 kJ =6.15 kJ/°C * (T_f-21,5^0C)

21.84 KJ = (6.15 kJ/^0C * T_f) - (6.15 kJ/^0C*21.5^0C)

21.84 KJ = (6.15 kJ/^0C * T_f) - 132.225 kJ

21.84 KJ + 132.225 kJ = (6.15 kJ/^0C * T_f)

154.065 kJ = (6.15 kJ/^0C * T_f)

T_f = \frac{154.065kJ}{6.15kJ/^0C}

T_f =25.05°C

4 0
4 years ago
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