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Alex777 [14]
3 years ago
12

An object traveling around another object in space is in what?

Physics
1 answer:
Gnoma [55]3 years ago
8 0

Answer:

is called an orbit

Explanation:

a satellite is any natural or artificialobject that revolves around an object in space, just as the moon revolvesaround Earth.

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Which statement correctly describes the current in a circuit that is made up of any two resistors connected in parallel with a b
AysviL [449]
B is the answer I think
8 0
3 years ago
Suppose an object’s initial velocity is 10 m/s and its final velocity is 4 m/s. Mass is constant.
Ostrovityanka [42]

The correct answer is:

Work is negative, the environment did work on the object, and the energy of the system decreases.

In fact, the work-energy theorem states that the work done by the system is equal to its variation of kinetic energy:

W=\Delta K=K_f -K_i

In this problem, the variation of kinetic energy \Delta K is negative (because the final velocity is less than the initial velocity), so the work is negative, and this means that the environment did work on the object, and its energy decreased.

3 0
3 years ago
Read 2 more answers
The rainbow is a result of a. Diffraction of the light.
suter [353]

Rainbows are caused by the dispersion of light, which itself consists of a combination of refraction and reflection of light around little droplets of water.

Choice C

5 0
3 years ago
Which type of bond is responsible for the attraction of one water molecule to another
cupoosta [38]

The answer is NOT covalent , it is Hydrogen .

3 0
3 years ago
A steel cable has a cross-sectional area 4.49 × 10^-3 m^2 and is kept under a tension of 2.96 × 10^4 N. The density of steel is
Lemur [1.5K]

Answer:

The transverse wave will travel with a speed of 25.5 m/s along the cable.

Explanation:

let T = 2.96×10^4 N be the tension in in the steel cable, ρ  = 7860 kg/m^3 is the density of the steel and A = 4.49×10^-3 m^2 be the cross-sectional area of the cable.

then, if V is the volume of the cable:

ρ = m/V

m = ρ×V

but V = A×L , where L is the length of the cable.

m = ρ×(A×L)

m/L = ρ×A

then the speed of the wave in the cable is given by:

v = √(T×L/m)

  = √(T/A×ρ)

  = √[2.96×10^4/(4.49×10^-3×7860)]

  = 25.5 m/s

Therefore, the transverse wave will travel with a speed of 25.5 m/s along the cable.

7 0
3 years ago
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