Refer to the diagram shown below.
m = the mass of the medal
T = the tension in the string
g = 9.8 m/s²
Part (a)
The inertial force, F, tends to move the medal away from the windshield when the vehicle accelerates to the right.
Answer: The medal leans away from the windshield.
Part (b)
For force balance,
T cos(15°) = mg
0.9659 T = 9.8m
T = 10.1457m N
Also,
F = Tsin(15°) = 10.1457m*0.2588 = 2.6257m N
The inertial force is equal to the accelerating force, therefore
the acceleration, a, is given by
(2.6257m N) = (m kg)*(a m/s²)
a = 2.6257 m/s²
Answer: 2.626 m/s²
m = the mass of the medal
T = the tension in the string
g = 9.8 m/s²
Part (a)
The inertial force, F, tends to move the medal away from the windshield when the vehicle accelerates to the right.
Answer: The medal leans away from the windshield.
Part (b)
For force balance,
T cos(15°) = mg
0.9659 T = 9.8m
T = 10.1457m N
Also,
F = Tsin(15°) = 10.1457m*0.2588 = 2.6257m N
The inertial force is equal to the accelerating force, therefore
the acceleration, a, is given by
(2.6257m N) = (m kg)*(a m/s²)
a = 2.6257 m/s²
Answer: 2.626 m/s²