Answer:

Explanation:
1. Moles of CCl₄

2. Molar mass of CCl₄
MM = 1 × 12.01 + 4 × 35.5 = 12.01 + 142 = 154.0 g/mol
3. Mass of CCl₄

4. Volume of CCl₄

The compound is sodium chloride
Answer:
Using Phosphoric acid will work perfectly for producing Hydrogen halides because its not an Oxidizing agent. ...
Using an ionic chloride and Phosphoric acid
H3PO4 + NaCl ==> HCl + NaH2PO4
H3PO4 + NaI ==> HI + NaH2PO4
H2SO4 + NaCl ==> HCl + NaHSO4
This method(Using H2So4) will work for all hydrogen hydrogen halide except Hydrogen Iodide and Hydrogen Bromide.
The Sulphuric acid won't be useful for producing Hydrogen Iodide because its an OXIDIZING AGENT. Whist producing the Hydrogen Iodide... Some of the Iodide ions are oxidized to Iodine.
2I-² === I2 + 2e-
Explanation:
Only one molecule have <u>sp2 </u>hybridization on central atom and that is <u>SO₂</u>.
<u>XeCl₂</u> have <u>sp3d </u>hybridization.
<u>OCl₂</u> have <u>sp3 </u>hybridization.
<u>HCN </u>have <u>sp </u>hybridization.
Hybridization is defined as the concept of mixing two atomic orbitals to give rise to a new type of hybridized orbitals.
Hybridization intermixing usually results in the formation of hybrid orbitals having entirely different energies, shapes, etc.
Learn more about hybridization here:- brainly.com/question/22765530
#SPJ4
Answer:
6.23 x 10^23 molecules
Explanation:
First find the number of moles of BH3 from the information given. We know the amount of grams present and we can find the molar mass which is 13.84.
We know that moles is grams divided by molar mass so we get 14.32/13.84 which is 1.03 moles.
Finally, to figure out the number of molecules, we multiply 1.03 by Avogadro's number which is 6.022x10^23 and we get 6.23x10^23 molecules.