All categories

3 years ago

Find the sum -1,457+890+(-345)=

Mathematics

1 answer:

QveST [7]3 years ago

5 0

Answer:

-912

Step-by-step explanation:

Simplify: -1,457 + 890 - 345
-1,457 + 890 = -567
Plug -567 in: -567 - 345
-567 - 345 = -912

I hope this helps!

You might be interested in

I’m confused on this one

Naddik [55]

Remark

The intersecting chord theorem states that when 2 chords intersect, the product of the parts of one chord = the product of the 2 parts of the other chord.

In this case ML * LE = IL * LS

Givens

ML = x; LE = 12; IL = 9; LS = 4

Substitute and Solve

12x = 9*4

12x = 36 Divide by 12

x = 36/12

x = 3 Answer <<<<<

8 0

3 years ago

A group of 20 students in four adults are going on a field trip to the museum What is the ratio of students to adults complete t

stepladder [879]

Answer:

5:1

Step-by-step explanation:

Originally the ratio is 20:4

but then it is simplified to 10:2

then 5:1

6 0

2 years ago

Find the product using model or drawing

antiseptic1488 [7]

Fraction multiplication involves multiplying the numerators and the denominators to get the numerator and the denominator of the product respectively

Please find the attached diagrams

1. $\dfrac{2}{15}$ , 2. $\dfrac{3}{8}$ , 3. $\dfrac{1}{12}$ , 4. $\dfrac{7}{21}$ , 5. $\dfrac{3}{10}$

6. 51, 7. 1, 8. 22, 9. $\dfrac{36}{55}$ , 10. $5\dfrac{1}{3}$

Reasons:

The process of multiplication of factors using a model includes;

Creating a table that have the number of rows and columns equal to the values in the denominator of the two fractions respectively

Shading the number of columns given by the numerator of the fraction that has a denominator equal to the number of columns in the table

Shading the number of rows given by the numerator of the fraction that has a denominator equal to the number of rows in the table

Ensuring that the common area are shaded to a different color

Simplifying the result

1. $\dfrac{2}{3} \times \dfrac{1}{5} = \dfrac{2}{15}$

2. $\dfrac{1}{2} \times \dfrac{3}{4} = \dfrac{3}{8}$

3. $\dfrac{1}{4} \times \dfrac{2}{6} = \dfrac{2}{24} = \dfrac{1}{12}$

4. $\dfrac{1}{7} \times \dfrac{2}{3} = \dfrac{7}{21}$

5. $\dfrac{4}{8} \times \dfrac{3}{5} = \dfrac{12}{40} = \dfrac{3}{10}$

Second part

6. When calculating fractions, 'of' means to 'multiply by', therefore, we have;

$\dfrac{17}{25} \times 75= \dfrac{17}{25} \times 25 \times 3 = 17 \times 3 = 51$

7. $\dfrac{7}{6} \times \dfrac{24}{28} = \dfrac{7}{6} \times \dfrac{6 \times 4}{7 \times 4} = \dfrac{7}{6} \times \dfrac{6}{7 } = 1$

8. $12 \times 1\dfrac{5}{6} =6 \times 2 \times \dfrac{11}{6} =2 \times {11} = 22$

9. $\dfrac{4}{5} \times \dfrac{9}{11} = \dfrac{4 \times 9}{5 \times 11} = \dfrac{36}{55}$

10. $6\dfrac{2}{3} \times \dfrac{12}{15} =\dfrac{20}{3} \times \dfrac{12}{15} = \dfrac{4 \times 5}{3} \times \dfrac{4 \times 3}{5 \times 3} = \dfrac{4}{3} \times {4} = \dfrac{16}{3} = 5\dfrac{1}{3}$