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Hoochie [10]
3 years ago
12

Which balloon would fall faster, water filled or murcury filled?

Physics
1 answer:
bazaltina [42]3 years ago
7 0
A mercury filled balloon would fall faster then water. Mercury is heavier.
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If you stretch a rubber hose and pluck it, you can observe a pulse traveling up and down the hose.(i) What happens to the speed
Monica [59]

The thing that happens to the speed of the pulse when you stretch the hose more tightly is that it increases.

<h3>What is wage speed?</h3>

It should be noted that wave speed simply means the distance that a wave travels during a particular time.

It should be noted that higher tension leads to an increase in the speed of the wave.

Therefore, the thing that happens to the speed of the pulse when you stretch the hose more tightly is that it increases.

Learn more about speed on:

brainly.com/question/13943409

#SPJ4

4 0
1 year ago
Why doesn't the skateboarder rolls as high up the ramp each time you go down the ramp ​
Alexandra [31]
Because of the law of inertia and it’s effect on the skater
5 0
3 years ago
20 points and brainiest
DIA [1.3K]

Answer:

electrical energy sometimes.

Explanation:

125.0m

300 degree Fahrenheit

7 0
3 years ago
X<br> x<br> 2.5 N<br> 1.7 N<br> 2.5 N
Olin [163]

Answer:

2.5*1.7/2.5

Explanation:

6 0
2 years ago
An electron with a speed of 1.2 × 107 m/s moves horizontally into a region where a constant vertical force of 5.2 × 10-16 N acts
Aliun [14]

Answer: 0.642mm

Explanation: F= force = 5.2×10^-16 N,

v = velocity of electron = 1.2×10^7 m/s,

m = mass of electron = 9.11×10^-31 kg.

We will assume the motion of the object to be of a constant acceleration, hence newton's laws of motion is applicable.

Recall that f = ma.

Where a = acceleration

This acceleration of vertical because it occurred when the object deflected.

5.2×10^-16 = 9.11×10^-31 (ay)

ay = 5.2×10^-16 / 9.11×10^-31

ay = 5.71×10^14 m/s²

For the horizontal motion, x = vt

Where x = horizontal distance = 0.019m and v is the velocity = 1.2×10^7 m/s,

By substituting the parameters, we have that

0.019 = 1.27×10^7 × t

t = 0.019 / 1.27 × 10^7

t = 1.5×10^-9 s

The vertical distance (y) is gotten by using the formulae below

y = ut + at²/2

but u = 0

y = at²/2

y = 5.71×10^14 × (1.5×10^-9)²/2

y = 0.00128475/2

y = 0.000642m = 0.642mm

7 0
3 years ago
Read 2 more answers
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