Answer:
25 m
Explanation:
The relationship between Velocity, distance and time is given as
S = v/t........................... Equation 1
Where S = average velocity of the car, d = distance covered by the car, t = time
Making d the subject of the equation,
d = vt.................... Equation 2
Given: v = 6.25 m/s, t = 4.00 s.
Substitute into equation 2,
d = 6.25(4)
d = 25 m.
Hence, the distance traveled by the car = 25 m
Answer:
<h3>The answer is 1.2 m</h3>
Explanation:
In order to find the distance covered we use the formula
<h3>distance = velocity × time</h3>
From the question
velocity = 0.24 m/s
time = 5 s
We have
distance = 0.24 × 5
We have the final answer as
<h3>1.2 m</h3>
Hope this helps you
Given
Inital velocity U = 50km/ hour = 250/18 m/sec
Final velocity =?
Acceleration = 4 m/sec^2
Time = 3 sec
Third equation of motion : (Final velocity)^2 - (initial velocity)^ 2 = 2 * acceleration * displacement
That is :
V^2 - U ^2 = 2aS
First equation of motion : S = ut + 1/2at^2
Calculating S :
Bringing units to same scale , we get : 50km/hour = 50*( 5/18) m/sec = 250 /18 m/sec
S = (250/18) * 3 + 1/2 ( 4 ) (3)^2
=(250 / 6 ) + 18 = 358/ 6
Putting S in third equation of motion, we get
V^2 - U ^2 = 2aS
V^2 - (250/18)^2 = 2 * 4 * 358/6
V is approximately 25.9 m/sec ~ 26
V = 26 * 18/5 = 93 km/hour
Answer:
Explanation:
Lead has an half life of 43.5 seconds
The radioactive decay law says
N(t) = No•2^(-t / t½)
Hence, the percent of a sample of the Lead-214 isotope that decay after a time equivalent to 7 half-lives
N(t) = No•2^(-t / t½)
N(t) / No = 2^(-t / t½)
N(t) / No = 2^-7
N(t) / No = 7.81 × 10^-3
To percentage
N(t) / No = 7.81 × 10^-3 × 100
N(t) / No = 0.781 %
