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Anna [14]
3 years ago
7

Violet light (410 nm) and red light

Physics
1 answer:
Leokris [45]3 years ago
7 0

Answer:10.03

Explanation:acellus

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Can someone help with question.
Katarina [22]

Answer:

IDK

Explanation:

IDK

5 0
3 years ago
A car travels in the + x-direction on a straight and level road. For the first 4.00 s of its motion, the average velocity of the
sergejj [24]

Answer:

25 m

Explanation:

The relationship between Velocity, distance and time is given as

S = v/t........................... Equation 1

Where S = average velocity of the car, d = distance covered by the car, t = time

Making d the subject of the equation,

d = vt.................... Equation 2

Given: v = 6.25 m/s, t = 4.00 s.

Substitute into equation 2,

d = 6.25(4)

d = 25 m.

Hence, the distance traveled by the car = 25 m

8 0
4 years ago
3 A spider runs along the top of a wall at a speed of 0.24 m/s. How far will it run<br> in 5 s?
PtichkaEL [24]

Answer:

<h3>The answer is 1.2 m</h3>

Explanation:

In order to find the distance covered we use the formula

<h3>distance = velocity × time</h3>

From the question

velocity = 0.24 m/s

time = 5 s

We have

distance = 0.24 × 5

We have the final answer as

<h3>1.2 m</h3>

Hope this helps you

4 0
3 years ago
3.
PilotLPTM [1.2K]
Given
Inital velocity U = 50km/ hour = 250/18 m/sec
Final velocity =?
Acceleration = 4 m/sec^2
Time = 3 sec
Third equation of motion : (Final velocity)^2 - (initial velocity)^ 2 = 2 * acceleration * displacement
That is :
V^2 - U ^2 = 2aS
First equation of motion : S = ut + 1/2at^2
Calculating S :
Bringing units to same scale , we get : 50km/hour = 50*( 5/18) m/sec = 250 /18 m/sec
S = (250/18) * 3 + 1/2 ( 4 ) (3)^2
=(250 / 6 ) + 18 = 358/ 6
Putting S in third equation of motion, we get
V^2 - U ^2 = 2aS
V^2 - (250/18)^2 = 2 * 4 * 358/6
V is approximately 25.9 m/sec ~ 26
V = 26 * 18/5 = 93 km/hour
5 0
1 year ago
Lead-214 has a half-life of 43.5 seconds. What percent of a sample of this isotope would be left after a time equivalent to 7 ha
pshichka [43]

Answer:

Explanation:

Lead has an half life of 43.5 seconds

The radioactive decay law says

N(t) = No•2^(-t / t½)

Hence, the percent of a sample of the Lead-214 isotope that decay after a time equivalent to 7 half-lives

​N(t) = No•2^(-t / t½)

N(t) / No = 2^(-t / t½)

N(t) / No = 2^-7

N(t) / No = 7.81 × 10^-3

To percentage

N(t) / No = 7.81 × 10^-3 × 100

N(t) / No = 0.781 %

6 0
3 years ago
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