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gregori [183]
3 years ago
13

What is the molarity of a solution that is prepared by adding 57.1 g of toluene (c 7 ​ h 8 ​ ) (density = 0.867 g/ml) to a 250 m

l volumetric flask, and then filling to the mark with benzene (c 6 ​ h 6 ​ ) (density = 0.876 g/ml)?
Chemistry
1 answer:
Virty [35]3 years ago
4 0

Answer:

2.48 mol/L.

Explanation:

  • The molarity of the solution can be expressed as <em>the number of moles of solute in 1.0 liter of the solution, </em>(M = n / V).
  • It is also can be calculated from the relation:

<em>M = (mass / molar mass) solute x (1000 / V of solution)</em>

The solute is toluene and the solvent is benzene.

mass of toluene (solute) = 57.1 g,

molar mass of toluene (solute) = 92.14 g/mol.

volume of the solution = 250 ml.

∴ M =  (mass / molar mass) solute x (1000 / V of solution) = [(57.1 g / 92.14 g/mol) x (1000 / 250 ml)] = 2.48 mol/L.

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To solve this problem, we need to obtain the number of moles of the solute we desired to prepare;

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