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gregori [183]
4 years ago
13

What is the molarity of a solution that is prepared by adding 57.1 g of toluene (c 7 ​ h 8 ​ ) (density = 0.867 g/ml) to a 250 m

l volumetric flask, and then filling to the mark with benzene (c 6 ​ h 6 ​ ) (density = 0.876 g/ml)?
Chemistry
1 answer:
Virty [35]4 years ago
4 0

Answer:

2.48 mol/L.

Explanation:

  • The molarity of the solution can be expressed as <em>the number of moles of solute in 1.0 liter of the solution, </em>(M = n / V).
  • It is also can be calculated from the relation:

<em>M = (mass / molar mass) solute x (1000 / V of solution)</em>

The solute is toluene and the solvent is benzene.

mass of toluene (solute) = 57.1 g,

molar mass of toluene (solute) = 92.14 g/mol.

volume of the solution = 250 ml.

∴ M =  (mass / molar mass) solute x (1000 / V of solution) = [(57.1 g / 92.14 g/mol) x (1000 / 250 ml)] = 2.48 mol/L.

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In a chemical reaction, where is the catalyst located
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Answer:

A. on the reactant side

Explanation:

A catalyst will appear in the steps of a <u>reaction mechanism</u>, but it will not appear in the overall chemical reaction

6 0
3 years ago
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8. A sample of potassium chlorate (KCIO,) was heated in a test tube and decomposed 2KC?(s) 302 (g) + 2KCIO, (s) The oxygen was c
dangina [55]

Answer:

Partial pressure of O_{2} in the gas was 733 torr and mass of KClO_{3} in the sample was 2.12 g.

Explanation:

a) Total pressure of gas = (partial pressure of water vapour)+(partial pressure of O_{2})

Here partial pressure of water vapour is 21 torr and total pressure of gas is 754 torr.

So, partial pressure of O_{2}= (total pressure of gas)-(partial pressure of water vapour) = (754 torr) - (21 torr) = 733 torr

b) Lets assume that O_{2} behaves ideally. Hence-

                                            PV=nRT

where P is pressure of O_{2}, V is volume of O_{2} , n is number of moles of O_{2} , R is gas constant and T is temperature in kelvin

here P = 733 torr = (733\times 0.001316)atm = 0.9646 atm

        V = 0.65 L, R = 0.082 L.atm/(mol.K), T=(273+22)K = 295 K

   So, n=\frac{PV}{RT}

                   = \frac{(0.9646 atm)\times (0.65 L)}{(0.082 L.atm/(mol.K))\times (295 K)}

                   = 0.0259 moles

As 3 moles of O_{2} are produced from 2 moles of KClO_{3} therefore 0.0259 moles of O_{2} are produced from (\frac{2\times 0.0259}{3}) moles or 0.0173 moles of KClO_{3}.

Molar mass of KClO_{3}= 122.55 g

So mass of KClO_{3} in sample = (0.0173\times 122.55)g

                                                                    = 2.12 g

7 0
3 years ago
PLEASE HELP MEEEEE (using 98 points to post)
Gekata [30.6K]
Δt = i Kf m

2.86 °C = (1) (1.86 °C kg mol-1) (x / 0.750 kg)

2.86 °C = (2.48 °C mol-1) (x)

x = 1.1532 mol

33.7 g / 1.1532 mol = 29.2 g/mol


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3 years ago
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Lithium has two isotopes, lithium-6 weighing 6.015 amu (7.5% abundance), and lithium-7
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Answer:

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Explanation:

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3 years ago
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Answer:

You need two potassium atom to form an ionic bond with one sulfur atom. Pottassium ions are formed by donating losing their electrons in the outermost shell, thr lost electrons are gained by sulphur atom to form 2K+ and S2-, respectively. The attraction between the positive ions and negative ions gives rise to the ionic bond and the molecular formula is K2S

Explanation:

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