Answer:
1.99 x 10⁻¹⁸J
Explanation:
Given parameters:
Frequency of the wave = 3 x 10¹⁵Hz
Unknown:
Energy of the photon = ?
Solution:
To solve this problem, we use the expression below;
E = hf
Where E is the energy, h is the Planck's constant and f is the frequency
Now insert the parameters and solve for E;
E = 6.63 x 10⁻³⁴ x 3 x 10¹⁵ = 19.9 x 10⁻¹⁹J or 1.99 x 10⁻¹⁸J
Answer:
Density is mass over volume.
Explanation:
Answer:
is reduced in the reaction
Explanation:
The given reaction is
The oxidation number of 
is changed from 
And The oxidation number of 
is changed from 
Hence, 
is oxidized and is reduced
You could test how high the soda shoots up when you drop mentos in different types of soda. i did it when i was in 6th grade
