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Iteru [2.4K]
3 years ago
11

When you rub an inflated balloonon your head on a dry day,it can make your hair stand up! what force is that?

Chemistry
1 answer:
Ket [755]3 years ago
4 0

When you rub an inflated balloon on your head and it makes your hair stand up, the force that makes the hair stand up is known as static electricity.

When the balloon is rubbed on the head, electrons from the hair atoms move into the balloon, thus making the balloon to be negatively charged and the hair positively charged due to loss of electrons.

Unlike charges attracts. Thus, when you try to pull the balloon away slowly, the positively charged hair and the negatively charged balloon will attract each other and this is usually what makes the hair stand up.

More on static electricity can be found here: brainly.com/question/24160155

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Which of the following is not an example of a chemical change?
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it's D tearing

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Particle Q has 16protons, 17neutrons and 18 electrons. Particle Q is:
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Write the full ground-state electron configuration for each element. (a) s:
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[Ne] 3s² 3p⁴ is the electronic configuration of sulfur in ground state
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A. 207 kJ<br> B. 4730 kJ<br> C. 9460 kJ<br> D. 414 kJ
Leno4ka [110]

Answer:

\boxed {\boxed {\sf C. \ 9460 \ kJ}}

Explanation:

The formula we must use is given to us:

q=mL_{vapor}

q is the energy, m is the mass, and L(vapor) is the latent heat of vaporization.

The energy is what we calculate and the mass is 2 kilograms. We need to find the latent heat of vaporization, which is on the table.

  • We know the sample is copper.
  • Find that element on the table, then the third box tells us it's latent heat of vaporization is 4730 kJ/kg

Now we know:

m= 2 \ kg \\L_{vapor}=4730 \ kJ/kg

Substitute the values into the formula.

q=(2 \ kg ) * (4730 \ kJ/kg)

Multiply. Note that the kilograms (kg) will cancel each other out.

q= 2* 4730 \ kJ

q= 9460 \ kJ

<u>9460 kilojoules</u> are required to vaporize 2 kilograms of copper.

3 0
3 years ago
If the reaction N2 (g) + 3 H2 (g) --&gt; 2 NH3 (g) has the concentrations 1.1 M for nitrogen, 0.75 M for hydrogen and 0.25 M fo
Luba_88 [7]

<u>Answer:</u> The value of K_c is 0.136 and is reactant favored.

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{c}

For the chemical reaction between carbon monoxide and hydrogen follows the equation:

N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)

The expression for the K_{c} is given as:

K_{c}=\frac{[NH_3]^2}{[N_2][H_2]^3}

We are given:

[NH_3]=0.25M

[H_2]=0.75M

[N_2]=1.1M

Putting values in above equation, we get:

K_c=\frac{(0.25)^2}{1.1\times (0.75)^3}

K_c=0.135

There are 3 conditions:

  • When K_{c}>1; the reaction is product favored.
  • When K_{c}; the reaction is reactant favored.
  • When K_{c}=1; the reaction is in equilibrium.

For the given reaction, the value of K_c is less than 1. Thus, the reaction is reactant favored.

Hence, the value of K_c is 0.136 and is reactant favored.

4 0
3 years ago
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