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gayaneshka [121]
3 years ago
8

A town has a population of 17000 and grows at 2.5% every year. To the nearest year how long Will it be until The population will

reach 23600
Mathematics
1 answer:
Makovka662 [10]3 years ago
4 0

Answer:

almost 15.5 years

Step-by-step explanation: let the population will be reached in t years

17000+(17000x2.5%xt) = 23600

or, 17000 x (1+ 2.5% x t) = 23600

or, 1+ 2.5% x t = 23600/17000

or, 1+ 2.5% x t = 236/170

or, 2.5% x t = 236/170 - 1

or, 2.5% x t = 66/170

or, t = 66/(170 x 2.5%)

t= 15.529

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To answer, it is assumed that e here is the Euler number which is equal to 2.718. Substitute this value to the e of the second equation to get the value of b.
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Then, we substitute this value to the first equation to get the value of a.
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3 years ago
Can someone help? This is so hard
Sunny_sXe [5.5K]

Answer:

#1 x = 31°

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Step by Step Explanation:

#1

  • By the theorem of intersecting secants outside of the circle, we have:

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#2

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IRISSAK [1]

Answer:

<h2>The x-interecepts are 5.6 and -1.4, approximately.</h2>

Step-by-step explanation:

The given equation is

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Where a=5, b=-21 and c=39, let's use the quadratic formula

x_{1,2}=\frac{-b(+-)\sqrt{b^{2}-4ac } }{2a} =\frac{-(-21) (+-)\sqrt{(-21)^{2} -4(5)(-39)} }{2(5)}\\ x_{1,2}=\frac{21(+-)\sqrt{441+780} }{10}=\frac{21(+-35)}{10}\\x_{1}=\frac{21+35}{10}=\frac{56}{10} \approx 5.6\\  x_{2}=\frac{21-35}{10}=\frac{-14}{10} \approx -1.4

Therefore, the x-interecepts are 5.6 and -1.4, approximately.

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