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Illusion [34]
3 years ago
8

Two experiments were conducted in a bomb calorimeter. The first one to determine the heat capacity of the calorimeter, the secon

d the heat of combustion of the carcinogenic substance benzene (C6H6). a. In the first experiment, the temperature rises from 22.37 o C to 24.68 o C when the calorimeter absorbs 5682 J of heat. Determine the heat capacity of the calorimeter.
Chemistry
1 answer:
Alex787 [66]3 years ago
7 0

Answer: 2460J/g^0C

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=C\times \Delta T

Q = Heat absorbed by calorimeter =5682 Joules

C = heat capacity of calorimeter = ?

Initial temperature of the calorimeter = T_i = 22.37°C

Final temperature of the calorimeter = T_f  = 24.68°C

Change in temperature ,\Delta T=T_f-T_i=(24.68-22.37)^0C=2.31^0C

Putting in the values, we get:

5682=C\times 2.31^0C

C=2460J/g^0C

The heat capacity of the calorimeter is 2460J/g^0C

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3 years ago
I need help please, thanks!
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Answer:

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3 years ago
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andre [41]

Answer:

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