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kodGreya [7K]
3 years ago
14

What is the correct name for the cyclic alkane shown on the right?

Chemistry
1 answer:
NISA [10]3 years ago
5 0
What is the correct name for the cyclic alkane shown on the right? 1,3-dimethyl, 3-ethylcyclohexane 1-ethyl, 1,4-dimethylcyclohexane 1-ethyl-1,3-dimethylcyclohexane 1-ethyl-1,3-dimethylcyclopentane 1,3 dimethyl, 3- ethylcyclopentane A
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What controls the amount of product formed in a chemical reaction
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Answer: limiting reactant controls the amount of product formed in a chemical reaction.

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4 years ago
Nicolaas constructed a working model of the hydrologic cycle during science class. He used an open flame, liquid water, two larg
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Surface, condensation, evaporation, precipitation

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3 years ago
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If one ball with a momentum of 50 kg·m/s hits a ball at rest and no other forces are acting on either ball, what's the total mom
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5 0
4 years ago
The temperature of a sample of silver increased by 23.8 °C
PIT_PIT [208]

Answer:

46.67 g

Explanation:

From the question given above, the following data were obtained:

Change in temperature (ΔT) = 23.8 °C

Heat (Q) = 261 J

Specific heat capacity (C) of silver = 0.235 J/gºC

Mass of silver (M) =?

The mass of the sample of silver can be obtained as follow:

Q = MCΔT

261 = M × 0.235 × 23.8

261 = M × 5.593

Divide both side by 5.593

M = 261 / 5.593

M = 46.67 g

Thus, the mass of the sample of silver is 46.67 g

3 0
3 years ago
a 45g sample of water at 12°c is heated with 15kJ of energy. What will be the final temperature of the water?
Marizza181 [45]

Answer:

Final temperature  = 91.75  °C

Explanation:

Given data:

Mass of water = 45 g

Initial temperature = 12 °C

Energy required = 15 Kj (15000 j)

Final  temperature = ?

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Solution:

Q = m.c. ΔT

15000 j = 45 g × 4.18 j/g.°C × (T2 -T1)

15000 j = 45 g × 4.18 j/g.°C × (T2-  12 °C)

15000 j = 188.1 J/°C × (T2-  12 °C)

15000 j / 188.1 J/°C = T2-  12 °C

79.745 °C  = T2 - 12 °C

T2 = 79.745 °C +  12 °C

T2 = 91.75  °C

4 0
3 years ago
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