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Ipatiy [6.2K]
3 years ago
15

The rate law for the rearrangement of ch3nc to ch3cn at 800 k is rate = (1300 s-1)[ch3nc]. what is the half-life for this reacti

on?
Chemistry
1 answer:
Lana71 [14]3 years ago
3 0
The rate of reaction is always expressed in concentration per time like mol/L·s. The equation is:

r [mol/L·s] = kCⁿ, where n is the order of reaction. Since k is 1300/s, that means that Cⁿ = C such that (1/s)*(mol/L) = mol/L·s. Thus, n=1. For a first order reaction, the formula would be:

ln(A/A₀) = -kt
where
A is the amount of material after time t
A₀ is the amount of material at t=0

The half life is when A/A₀ = 1/2÷1 = 1/2. Thus, the half-life t is:

ln(1/2) = (-1300t)
t = 5.33×10⁻⁴ seconds
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using information in titles of appendices b and c, calculate the minimum grams of propane, C3H8 (g), that must be combusted to p
Lubov Fominskaja [6]

<u>Given:</u>

Mass of ice = mass of water = 5.50 kg = 5500 g

Temperature of ice = -20 C

Temperature of water = 75 C

<u>To determine:</u>

Mass of propane required

<u>Explanation:</u>

Heat required to change from ice to water under the specified conditions is:-

q = q(-20 C to 0 C) + q(fusion) + q (0 C to 75 C)

  = m*c(ice)*ΔT(ice) + m*ΔHfusion + m*c(water)*ΔT(water)

  = 5500[2.10(0-(-20)) + 334 + 4.18(75-0)] = 3792 kJ

The enthalpy change for the combustion of propane is -2220 kJ/mol

Therefore, the number of moles of propane corresponding to the required energy of 3792 kJ = 1 mole * 3792 kJ/2220 kJ = 1.708 moles of propane

Molar mass of propane = 44 g/mol

Mass of propane required = 1.708 moles * 44 g/mol = 75.15 g

Ans: 75.15 grams of propane must be combusted.



4 0
4 years ago
analysis of a compound indicates that it contains 1.04 grams K 0.70 g Cr and 0.86 g O. Find its empirical formula
MrMuchimi
1.04gK*1molK/39.01g K= 0.0267 mol K
0.70gCr*1mol/52.0g Cr = <span>0.0135 mol Cr   
0.86 gO* 1 mol/16.0 g O = 0.0538 mol O
</span>0.0267 mol K/0.0135 = 2 mol K
0.0135 mol Cr  /0.0135= 1 mol Cr
 0.0538 mol O/0.035= 4 mol Cr
K2CrO4
6 0
3 years ago
Read 2 more answers
What is tantalum's electron configuration?
lakkis [162]

Answer:

Xe 4f14 5d3 6s2

Explanation:

4 0
3 years ago
Read 2 more answers
If 1.20 moles of copper react with mercuric nitrate how many moles of mercury form
Andrej [43]
Reaction of Copper with Mercuric Nitrate is as follow,

                       Cu  +  Hg(NO₃)₂    →    Cu(NO₃)₂  +  Hg

According to equation,

                            1 Mole of Cu reacts to form  =  1 Mole of Hg

So,

           1.20 Moles of Cu will react to produce  =  X Moles of Hg

Solving for X,

                                   X  =  (1.20 mol × 1 mol) ÷ 1 mol

                                   X  =  1.20 mol of Hg
Result:
          1.20 mole of Cu when reacted with mercuric nitrate produces 1.20 moles of Hg.
3 0
4 years ago
Is a 3.3% solution dilute or concentrated?<br><br><br><br> Dilute<br><br><br><br> Concentrated
Arisa [49]

Answer:

Dilute

Explanation:

A concentrated solutions is a one which has relatively large amount of dissolved solute in the solution whereas a dilute solution is a one which has relatively lower concentration of dissolved solute.

In the given solution there is only 3.3% of solute. So, we can say that the given solution is a dilute solution. However, these terms are relative.

6 0
3 years ago
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