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dmitriy555 [2]
3 years ago
8

How does the properties of matter in liquid and gas state allow the Herons fountain to work?

Chemistry
1 answer:
Varvara68 [4.7K]3 years ago
8 0

Answer:

Heron's fountain is an hydraulic machine that works because or the pressure inside of the system. Water will flow from high gravitational potential energy to low gravitational potential energy. The two sides of the system will present different pressure because they have different fluids in it (water and air) and  water pressure is higher than gas/air pressure, so it will flow.

It is important to take into account that the pressure in the columns is a function of the height of the fluid (water or air).

Explanation:

<u>The properties of liquid:</u>

- If a liquid is poured into a container, it will adapt to the container's shape

- In a liquid state, the molecules have a kinetic energy higher than in a solid state

- Liquid particles are not arranged in a regular way but they are very close  to each other, that's why liquids have a definite volume.

- Force is spread in an even way through a liquid, so the liquid particles are displaced if an object is placed in it.

- Liquids, as solids, can't be compressed

<u>The properies of gas:</u>

- They are everywhere

- Gas molecules are disorganized and have a great deal of space between them

- Gas fill up any container and spread indefinitely

- Gas molecules have a high kinetic energy

- If gas is put under pressure, the space between particles will decrease and collisions between them will increase.

- If the temperature of the gas increases in a container, the pressure will increase; if the temperature decreases, the pressure sill decrease.

- It can be compressed

- Gas has no definite volume nor definite shape.

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Ammonia will decompose into nitrogen and hydrogen at high temperature. An industrial chemist studying this reaction fills a tank
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Complete Question

The complete question is shown on the first uploaded image

Answer:

The concentration equilibrium constant is K_c  = 14.39

Explanation:

The chemical equation for this decomposition of ammonia is

                2 NH_3  ↔   N_2 + 3 H_2

The initial concentration of ammonia is mathematically represented a

          [NH_3] =  \frac{n_1}{V_1}  = \frac{29}{75}

          [NH_3] = 0.387  \  M

The initial concentration of nitrogen gas  is mathematically represented a

         [N_2] =  \frac{n_2}{V_2}

         [N_2] =  0.173  \  M

So  looking at the equation

   Initially (Before reaction)

      NH_3 = 0.387 \ M

      N_2  =  0 \  M

      H_2 =  0 \ M

During reaction(this is gotten from the reaction equation )

        NH_3 = -2 x(this implies that it losses two moles of concentration )

         N_2 = + x  (this implies that it gains 1 moles)

         H_2  =  +3 x(this implies that it gains 3 moles)

Note : x denotes concentration

At equilibrium

        NH_3 = 0.387 -2x

       N_2 =  x

        H_2  =  3 x

Now since

     [NH_3] = 0.387  \  M

     x= 0.387  \  M    

H_2  =  3 * 0.173    

H_2  =  0.519 \ M    

NH_3 = 0.387 -2(0.173)

NH_3 = 0.041 \ M

Now the equilibrium constant is

           K_c  =  \frac{[N_2][H_2]^3}{[NH_3]^2}

substituting values

           K_c  =  \frac{(0.173) (0.519)^3}{(0.041)^2}

           K_c  = 14.39

         

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