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Wewaii [24]
3 years ago
13

A certain compound is made up of one phosphorus (P) atom, three chlorine (Cl) atoms, and one oxygen (O) atom. What is the chemic

al formula of this compound?
Chemistry
1 answer:
user100 [1]3 years ago
5 0
<span> POCl3 is the correct way to write the chemical formula for this compound</span>
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In your own words, explain how gametes (the cells made for sexual reproduction) differ from normal body cells.
NNADVOKAT [17]

Answer:

gametes have to become haploid - they have to reduce their genetic material to a single copy, while somatic cells are diploid

Explanation:

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Definition of phosphoric acid
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<em>Phosphoric acid is an acid used in fertilizers and soaps.</em>

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8 0
3 years ago
A container initially holds 1.24mol of hydrogen gas and has a volume of 27.8L. Hydrogen gas was added to the container, and the
Fantom [35]

Answer:

After increasing the volume, we have 1.81 moles of hydrogen gas in the container

Explanation:

Step 1: Data given

Number of moles hydrogen gas (H2) = 1.24 moles

Volume of hydrogen gas (H2° = 27.8 L

The final volume is increas to 40.6 L

Step 2: Calculate the new number of moles

V1/n1 = V2/n2

⇒with V1 = the initial volume = 27.8 L

⇒with n1 = the initial number of moles H2 = 1.24 moles

⇒with V2 = the final volume = 40.6 L

⇒with n2 = the new number of moles = TO BE DETERMINED

27.8L / 1.24 moles = 40.6 L / n2

n2 = 40.6 / (27.8/1.24)

n2= 1.81 moles

After increasing the volume, we have 1.81 moles of hydrogen gas in the container

3 0
3 years ago
Calcium carbonate decomposes into calcium oxide and carbon dioxide. If 530 g of calcium carbonate decomposes, how many grams of
Rudik [331]

Answer:

233 g

Explanation:

Let's consider the following reaction.

CaCO₃ → CaO + CO₂

We can establish the following relations:

  • The molar mass of calcium carbonate is 100.09 g/mol.
  • The molar ratio of calcium carbonate to carbon dioxide is 1:1.
  • The molar mass of carbon dioxide is 44.01 g/mol

The mass of carbon dioxide produced from 530 g of calcium carbonate is:

530gCaCO_{3}\frac{1molCaCO_{3}}{100.09gCaCO_{3}} ,\frac{1molCO_{2}}{1molCaCO_{3}} .\frac{44.01gCO_{2}}{1molCO_{2}} =233gCO_{2}

8 0
2 years ago
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