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tresset_1 [31]
3 years ago
15

After school, Bruce skateboards directly from school to a skate park and then from the

Mathematics
1 answer:
ankoles [38]3 years ago
5 0
It’s 15 km. You need to take the root from 9^2 + 12^2 wich equals 15. You need to use pythagoras a^2 + b^= c^2
You might be interested in
Find the value of x and y (i need this asap please)
disa [49]
For a right triangle with 60° angle, and hypotenuse h=10√3,
x=h*sin(60)=10√ 3 * √3/2 = 30/2=15
y=h*cos(60)=10√3 * (1/2) = 5√3
3 0
3 years ago
Twenty percent of drivers driving between 10 pm and 3 am are drunken drivers. In a random sample of 12 drivers driving between 1
Lesechka [4]

Answer:

(a) 0.28347

(b) 0.36909

(c) 0.0039

(d) 0.9806

Step-by-step explanation:

Given information:

n=12

p = 20% = 0.2

q = 1-p = 1-0.2 = 0.8

Binomial formula:

P(x=r)=^nC_rp^rq^{n-r}

(a) Exactly two will be drunken drivers.

P(x=2)=^{12}C_{2}(0.2)^{2}(0.8)^{12-2}

P(x=2)=66(0.2)^{2}(0.8)^{10}

P(x=2)=\approx 0.28347

Therefore, the probability that exactly two will be drunken drivers is 0.28347.

(b)Three or four will be drunken drivers.

P(x=3\text{ or }x=4)=P(x=3)\cup P(x=4)

P(x=3\text{ or }x=4)=P(x=3)+P(x=4)

Using binomial we get

P(x=3\text{ or }x=4)=^{12}C_{3}(0.2)^{3}(0.8)^{12-3}+^{12}C_{4}(0.2)^{4}(0.8)^{12-4}

P(x=3\text{ or }x=4)=0.236223+0.132876

P(x=3\text{ or }x=4)\approx 0.369099

Therefore, the probability that three or four will be drunken drivers is 0.3691.

(c)

At least 7 will be drunken drivers.

P(x\geq 7)=1-P(x

P(x\leq 7)=1-[P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)+P(x=5)+P(x=6)]

P(x\leq 7)=1-[0.06872+0.20616+0.28347+0.23622+0.13288+0.05315+0.0155]

P(x\leq 7)=1-[0.9961]

P(x\leq 7)=0.0039

Therefore, the probability of at least 7 will be drunken drivers is 0.0039.

(d) At most 5 will be drunken drivers.

P(x\leq 5)=P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)+P(x=5)

P(x\leq 5)=0.06872+0.20616+0.28347+0.23622+0.13288+0.05315

P(x\leq 5)=0.9806

Therefore, the probability of at most 5 will be drunken drivers is 0.9806.

5 0
3 years ago
Can somebody please answer this
Ray Of Light [21]
It would be c that is the answer
8 0
3 years ago
The number of miles Ford trucks can go on one tank of gas is normally distributed with a mean of 350 miles and a standard deviat
kati45 [8]

Answer:

The probability that a randomly chosen Ford truck runs out of gas before it has gone 325 miles is 0.0062.

Step-by-step explanation:

Let <em>X</em> = the number of miles Ford trucks can go on one tank of gas.

The random variable <em>X</em> is normally distributed with mean, <em>μ</em> = 350 miles and standard deviation, <em>σ</em> = 10 miles.

If the Ford truck runs out of gas before it has gone 325 miles it implies that the truck has traveled less than 325 miles.

Compute the value of P (X < 325) as follows:

P(X

Thus, the probability that a randomly chosen Ford truck runs out of gas before it has gone 325 miles is 0.0062.

7 0
3 years ago
If your current examination mean is 97.2 and you receive a 99 on the next examination, what effect will this have?
mr Goodwill [35]

If you have an average of 97.2 on your current exam and you get a 99 on your next exam, your average will increase.

  • Mean in mathematics is the sum (total) of all the values in a set of data, such as numbers or measurements, divided by the total number of values.

  • To find the average, sum all the values ​​in the set. Then divide the total by the number of values.

We have the current examination mean, xold = 97.2

Now, we receive,  x = 99 on the next examination, the new mean will be:

xnew = (xold + x)/N

xnew = (97.2+99)/2

xnew = 196.2/2

xnew = 98.1  

The new average is 98.1

98.1 > 97.2

So if you score 99 on your next exam, your average will increase.

Learn more about mean here

brainly.com/question/1136789

#SPJ4

3 0
1 year ago
Read 2 more answers
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