-- Use the formula D=(1/2)·(g)·(t²) to calculate how long
it takes the flower pot to fall to the ground.
1.5 m = (1/2) · (9.8 m/s²) · (t²)
t² = (1.5 m) / (4.9 m/s²)
t = 0.554 second
-- Use the formula Distance = (speed)·(time) to calculate
how far the pot traveled horizontally in that amount of time.
Distance = (8 m/s) · (0.554 sec)
Distance horizontally = 4.43 meters
Answer:
it is easier in zig zag because youll fell less tired and feel more energetic and it will will feel as if it were shorter to go zig zag
Student 1 would have a power 467 W and student 2 would have a power of 433 W. The correct option is the fourth option - Student 1 would have 467 W, and Student 2 would have 433 W of power.
From the question,
We are to calculate the power each student would have to climb the flight of stairs.
Power can be calculated using the formula

Where
P is Power
F is the force
d is the distance
and t is the time
NOTE: The weight of the students represent the force
F = 700 N
d = 4 m
t = 6 s
∴ 
P = 467 W
F = 650 N
d = 4 m
t = 6 s
∴ 
P = 433 W
Hence, Student 1 would have a power 467 W and student 2 would have a power of 433 W. The correct option is the fourth option - Student 1 would have 467 W, and Student 2 would have 433 W of power.
Learn more here: brainly.com/question/18801566
Answer:
PART A)
External force will be 75 N
PART B)
distance moved will be 1.125 m
Explanation:
PART A)
Given that net force on the mower is

now we also know that friction force due to ground is given as

now we have



so external force will be 75 N
PART B)
deceleration due to friction when external force is removed from it


now we can find the distance by kinematics



so the distance moved will be 1.125 m
Answer:
a. 2.1 s
b.0.48 Hz
c. A=24cm
d. 72cm/s
Explanation:
An air-track glider attached to a spring oscillates between the 10.0 cm mark and the 57.0 cm mark on the track. The glider completes 15.0 oscillations in 31.0 s.What are the (a) period, (b) frequency, (c) amplitude, and (d) maximum speed of the glider?
What are the period,
period is the time taken for a wave particle to make one complete oscillation
a) 31 / 15 = 2.066 seconds
= 2.1 s
(b) frequency
: this the number of oscillation made in one seconds.
it is also the inverse of the period.
= oscillations / time
= 15/31= 0.48 Hz
(c) amplitude
: maximum displacement from the origin
amplitude = 1/2 of the difference of oscillation marks
= 1/2(57-10) = 47/2cm
23.5cm
A=24cm
(d) maximum speed of the glider?
V=ωA
angular frequency *Amplitude
V=a*pi*f*amplitude
2π x frequency x amplitude = maximum speed
= 2π x .48 x 24
=72.38 cm/s
72cm/s