Answer:
V = I * R
R = 2 / 3.5 = .571 ohms maximum resistance of wire
R = ρ L / A where R is proportional to L and inversely proportional to A
A = ρ L / R minimum area of wire
ρ = 1 / μ = 1.67E-8 ohm-m resistivity inverse of conductivity
A = 1.67E-8 ohm-m * 225 m / .571 ohm = 6.68E-6 m^2
A = 6.68 mm^2 since 1 mm^2 = 10-6 m^2 or 1 mm = 10-3 m
A = Π r^2 = 6.68 mm^2
r = (6.68 / 3.14)^1/2 mm = 2.13 mm radius of wire
d = 2 * r = 4.26 mm
Answer:
176.9N
Explanation:
The following data were given
wire length,L=37cm=0.37m
linear density=18g/m
tube length,=192cm=1.92m,
speed of sound,v=343m/s
Since it is an open-closed tube, the second harmonic frequency is expressed as
The relationship between the tension, linear density and second harmonic frequency is expressed as
Answer:
thanks for the points man
I think A is the correct answer because its high is more higher compared to the others, and the mass really does not matter, to know the gravitational potential energy, we need to know how high the object is located because gravity does not show any favor to an object that has more mass or an object that doesnt
