He answers is B It equals the rate of the formation of SO3
Try c I think is the most accurate one
The reaction between the lead iodide, PbI2 and sodium carbonate, Na2CO3, will form the chemical compounds, sodium iodide and lead carbonate as shown below.
PbI2 + Na2CO3 --> NaI + PbCO3
The white precipitate formed in the reaction is PbCO3.
Answer:
The AH+ for Br2() is 0 kJ/mol.
The AH+ for Hg() is 0 kJ/mol.
The AH; for N261) is 0 kJ/mol.
Explanation:
