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ololo11 [35]
3 years ago
10

How does adding an atom affect the position of existing atoms and lone pairs?

Chemistry
2 answers:
lubasha [3.4K]3 years ago
5 0
Adding an atom affect the position of existing atoms and lone pairs by changing the geomertry and <span>changing postion of the lone pairs and atoms so that they are furthest apart. Hope this answers the question. Have a nice day.</span>
alexandr402 [8]3 years ago
4 0

Answer:

Changes the geometry by decreasing the bond angles.

Explanation:

Before delving into the solution to the question, let us define few terms relating to the question.

ATOMS:

Atoms are said to be the smallest unit of a matter, although it has been proved that atoms contains particles such as proton, neutron and electrons. The three(that is proton, neutron, and electrons) are called the subatomic particles.

LONE PAIR:

Lone pairs are valence electrons pairs and they are found at the outer part of the atom shell.

Bond pairs: are pairs of electron responsible for bondings between atoms.

So, let us go back to the question. The electrons on the lone pairs and that of the bond pairs repels and then comes the addition of another atom. Upon this addition of atoms, strain will occur and they have to come closer, also in order to overcome this, the geometry has to change too from its original to the new one.

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Vlada [557]
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filtration: separates insolube solid from a liquid.  1st diagram
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1. two or mor, chemically bonded
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3 0
4 years ago
Kerosene, a common space-heater fuel, is a mixture of hydrocarbons whose "average" formula is C₁₂H₂₆.
padilas [110]

The calculated enthalpy of formation of kerosene is 365.4 kJ and heat produced is 78650.3 kJ

For this, we need the normal enthalpy of formation given below

ΔH∘f(CO2)=−393.5kJ/molΔH∘f(H2O)\s=−241.8kJ/molΔH∘f(O2)=0kJ/mol

We shall now determine the enthalpy of kerosene formation:

H rxn = 24 mol H f (CO2) + 26 mol H f (H2O) + 2 mol H f (C12H26) + 37 mol H f (O2) + 1.50 104 kJ = 9444 kJ + 6286.8 kJ + 1500 kJ 2 mol H f (C12H26) = 730.8 kJ H f (C12H26) = 365.4 kJ

Kerosene has a density of 0.74 g/mL.

Kerosene volume (V) equals 0.63 gallons, or 0.63 x 3785.4, or 2384. 8 mL.

We shall now calculate the mass (m) of kerosene:

ρ=mVm\s=ρ×Vm\s=0.749g/mL×2384.mLm\s=1786.2g

We shall now discover the heat that 1786 generated.

Two grams of kerosene

Kerosene's molar mass is 170.33 g/mol.

The mass of two moles of kerosene is equal to 2*170.33*340.66g.

1.50104kJ of heat are generated by 340.66 g of kerosene.

1786 produced heat.

Kerosene 2 grams = 1.50 104 kJ 340.66 1786.2 g = 78650.3 kJ

Learn more about enthalpy here-

brainly.com/question/13996238

#SPJ4

5 0
1 year ago
ANSWER FAST PLZZZ!!!!!!!!!!!!!
goldfiish [28.3K]

Answer:

1 and 2

Explanation:

1 is negative

2 is negative

3 is positive

5 0
4 years ago
In a titration of 0.35 M HCl and 0.35 M NaOH, how much NaOH should be added to 45.0 ml of HCl to completely neutralize the acid?
Bezzdna [24]
It would be the same amount. So, 45 ml of NaOH is required to be added to the 45 ml of HCI to neutralize the acid fully. Here is a brief calculation:

Firstly, here is your formula: M(HCI) x V(HCI) = M(NaOh) x V(NaOH) 
With the values put in: 0.35 x 45 = 0.35 x V(NaOH) 
= 45 ml. 
There is 45 ml of V(NaOH)

Let me know if you need anything else. :)

           - Dotz
6 0
3 years ago
Which of the following elements has two valence electrons?
lara31 [8.8K]
Beryllium, Magnesium, Calcium....etc have two valence electrons
5 0
3 years ago
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