Answer:
AS ACCORDING TO THE LAW OF MASS CONSERVATION
REACTANTS =PRODUCTS
THEREFORE,
223.4+96=MASS OF FE2O3
=319.4 FE203
Answer:
1.46g of PbCrO₄ are the theoretical yield
Explanation:
Theoretical yield is defined as the maximum amount of products that could be produced (Assuming a yield of 100%).
The reaction of Lead (II) nitrate with sodium chromate is:
Pb(NO₃)₂(aq) + Na₂CrO₄(aq) → PbCrO₄(s) + 2NaNO₃ (aq)
First, we need to find molar mass of each reactant in order to determine limiting reactant (As the reaction is 1:1, the reactant with the lower number of moles is the limiting reactant). The moles of the limiting reactant = moles of Lead (II) chromate (The precipitate):
<em>Moles Pb(NO₃)₂ -Molar mass: 331.21g/mol-</em>
1.50g * (1mol / 331.21g) = 4.53x10⁻³ moles Pb(NO₃)₂
<em>Moles Na₂CrO₄ -Molar mass: 161.98g/mol-</em>
1.75g * (1mol / 161.98g) = 0.0108 moles
Pb(NO₃)₂ is limiting reactant and moles of PbCrO₄ are 4.53x10⁻³ moles. The mass is:
4.53x10⁻³ moles PbCrO₄ * (323.19g / mol) =
<h3>1.46g of PbCrO₄ are the theoretical yield</h3>
It is usually neutral becase its is close to neutral number 7
The passive movement of molecules or ions across a plasma membrane by means of a transports protein located in the plasma membrane
Answer:
C. 2O₃ ⇌ 3O₂
Explanation:
Kp is the equilibrium constant calculated from the partial pressures of a gas-phase reaction equation.
For a general gas-phase reaction aA + bB ⇌ nC + xD
the expression for the Kp = (pC)ⁿ(pD)ˣ / (pA)ᵃ(pB)ᵇ
where pA = partial pressure of A; pB = partial pressure of B; pC = partial pressure of C; pD = partial pressure of D
From the given reaction in equilibrium; N₂ + 3H₂ ⇌ 2NH₃
Kp = (pNH₃)² / (pN₂)¹ * (pH₂)³ = 4/7
(pNH₃)² / (pN₂)¹ * (pH₂)³ = (2)²/ (1)¹ * (3)³
Therefore, number of mole of reactants and products is equivalent to partial pressure.
A. 2SO₂ ⇌ O₂ + 2SO₃
pSO₂ = 2, pO₂ = 1, pSO₃ = 2,
Kp = 2²/ (2² * 1²) = 4/4 = 1
B. N₂O₄ ⇌ 2NO₂
pN₂O₄ = 1, pNO₂ = 2
Kp = 2²/1² = 4
C. 2O₃ ⇌ 3O₂
pO₃ = 2, pO₂ = 3
Kp = 3³/2² = 27/4
D. PCl₅ ⇌ PCl₃ + Cl₂
pPCl₅ = 1, pPCl₃ = 1, pCl₂ = 1
Kp = (1¹ * 1¹) / 1¹ = 1