A is 3 square root 2
Since 3*6 is 18
Find the factors of 18
So we have 9 and 2
9 is a perfect square so it’s 3 with 2 inside radical
Answer:
The figure will result is cone ⇒ B
Step-by-step explanation:
<em>When a </em><em>right triangle is rotated about its vertical leg 360°</em><em>, then it formed </em><em>a cone</em><em> its radius is the horizontal leg of the triangle and its height is the vertical lege of the triangle</em>
<em />
In the given figure
∵ Triangle TRE is a right triangle
∴ The horizontal leg is RE
∴ The vertical leg is TR
∵ The triangle is rotated around the horizontal leg RE 360°
∴ It formed a cone its radius = TR and its height = RE
∴ The figure will result is the cone
Step-by-step explanation:
the max. value is when the smaller set (A) is completely contained in the larger set (B).
then n(A n B) is n(A) = 50.
the set intersection between A and B cannot get bigger than that. or A gets bigger ...
after all, the intersection means it is a set of all elements that exist in BOTH sets.
but then there must be other elements besides A and B in the universal set too, because n(universal set) = 96, and n(A u B) would be only 60.
the min. value could be the empty set or 0. but because n(universal set) = 96, and n(A) + n(B) = 110 and larger than 96, it means that there have to be some shared elements. at least 110 - 96 = 14 elements.
in this case there cannot be other elements in the universal set than A and B. and n(universal set) = n(AuB) = 96.
120
because 12X10 is 120 and he has 12 groups of 10
10.20
(-2-0)^2+(4-(-6))^2
4 + 100
104 square root=10.20
