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How many grams of NaCl are needed to prepare 1.20 liters of a 2.00 M solution?

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Explanation: no. of moles of NaCl = molarity X volume in litres = 2 X 1.2 = 2.4, and molar mass or mass of 1 mole of NaCl = 58.44 g, so 2.4 moles NaCl = 140.256 g

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