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taurus [48]
3 years ago
12

Suppose a helium-3 nuclide transforms into a helium-4 nuclide by absorbing a proton and emitting a positron. Complete the nuclea

r chemical equation below so that it describes this nuclear reaction.
Chemistry
1 answer:
saw5 [17]3 years ago
6 0

<u>Answer:</u> The nuclear equation for the conversion of He-3 nuclide to He-4 nuclide is given above.

<u>Explanation:</u>

Nuclear reaction are defined as the reactions in which nucleus of an atom is involved.

Positron emission is defined as the emission process in which positron particle is emitted. In this process, a proton gets converted to neutron and an electron neutrino particle.

_Z^A\textrm{X}\rightarrow _{Z-1}^A\textrm{Y}+_{+1}^0e

The chemical equation for the reaction of He-3 with a proton follows:

_2^3\textrm{He}+_1^1\textrm{H}\rightarrow _2^4\textrm{He}+_{+1}^0e

Hence, the nuclear equation for the conversion of He-3 nuclide to He-4 nuclide is given above.

You might be interested in
Given 2.14g of B2H6
Shkiper50 [21]

Answer:

(A) is 0.0773 mol B2H6

(C) is 2.79 x 10^23 H atoms

Explanation:

Questions (A) and (B) are the same.

2.14 g B2H6 x (1 mol B2H6/27.668g B2H6) = 0.0773 mol B2H6 (A)

<u>27.668 is the molar mass of B2H6 calculated from the period table: </u>

(2 x 10.81) + (6 x 1.008) = 27.668

1.008 is the mass of H and 10.81 is the mass of B

(C)

0.0773 mol B2H6 x (6 mol H/ 1 mol B2H6) x (6.022 x 10^23 H atoms/1 mol H)

= 2.79 x 10^23 hydrogen atoms

Further Explanation:

  • For every 1 mol of B2H6, there are 6 moles of H (indicated by the subscript)
  • 6.022 x 10^23 is Avogrado's number and it equals to 1 mol of anything
  • Avogrado's number can be in units of atoms, molecules, or particles
5 0
3 years ago
PLS
MrRissso [65]

Answer:

A decomposition reaction occurs when one reactant breaks down into two or more products. This can be represented by the general equation: AB → A + B. Examples of decomposition reactions include the breakdown of hydrogen peroxide to water and oxygen, and the breakdown of water to hydrogen and oxygen.

8 0
2 years ago
Solid calcium carbonate breaks down into carbon dioxide gas, oxygen gas, and solid calcium, write an equation for described reac
Savatey [412]

Answer:

CaCO₃ ------> CaO + CO₂

<em>Note: The breakdown products of solid calcium carbonate is not carbon dioxide gas, oxygen gas, and solid calcium. Rather, it is calcium oxide and carbon dioxide as shown in the reaction equation above.</em>

Explanation:

Calcium carbonate is a mineral which occurs in nature in rocks as calcite and limestone. It is also the main component of eggshells, snail shells, seashells and pearls. It has the molecular formula CaCO₃.

Calcium carbonate or limestone decomposes into calcium oxide and carbon dioxide when heated and the reaction is used to make quicklime and carbon dioxide gas. The equation of the reaction is given below:

CaCO₃ ------> CaO + CO₂

Calcium oxide, one of the products of The decomposition reaction is known as lime and is an important mineral used for many purposes such as reducing the acidity of soils, in the production of limelight, as well as serving as the main ingredient in cement.

The main use of calcium carbonate is in the construction industry as an ingredient of cement. Calcium carbonate is also an important mineral required by sea organisms for making their shells.

5 0
2 years ago
How does the structure of Ethane (C2H6) and Propane(C3H8) differ? Are they members of a Homologous series?
aksik [14]

Answer:

Ethane & propane are members of same homologous series : alkane which is indicated with Cn H2n+2

Explanation:

5 0
2 years ago
15 pts The drop down items have the same options for all sections labeled choose an item
tia_tia [17]

Answer:

#8 : 21.5 L of CH₄

#9 : 36 g of H₂O

#9 : 5.4 x 10²² molecules of CO₂

Explanation:

#8 : Part 1.

Data given:

no. of moles of CH₄ = 0.960 mol

volume of CH₄ = ?

Solution

volume can be calculated by following formula

          No. of moles = Volume of gas / molar volume

Rearrange the above equation

            Volume of gas = No. of moles x molar volume . . . . . . (1)

Where

molar volume = 22.4 L/mol

Put values in equation 1

           Volume of gas = 0.960 mol x 22.4 L/mol

           Volume of gas = 21.5 L

So,

By calculation 0.960 moles have 21.5 L volume of CH₄

_______________

#9 : Part 2.

Data given:

no. of moles of H₂O = 2.0 mol

mass of H₂O = ?

Solution

volume can be calculated by following formula

          No. of moles = mass in grams / molar mass

Rearrange the above equation

            mass in grams = No. of moles x molar mass . . . . . . (2)

Where

molar mass of H₂O = 2 (1) + 16

molar mass of H₂O = 18 g/mol

Put values in equation 2

      mass in grams = 2.0 mol x 18 g/mol

        mass in grams = 36 g

So,

By calculation 2.0 moles have 36 g mass of H₂O

________________

#10 : Part 3.

Data given:

volume of CO₂ = 2 L

no. of molecules of CO₂ = ?

Solution

First we have to find out number of moles of CO₂

Following formula will be used

          No. of moles = Volume of gas / molar volume

Where

molar volume = 22.4 L/mol

Put values in above equation

           No. of moles = 2 L / 22.4 L/mol

           No. of moles = 0.0893 mol

So,

No. of moles of CO₂ = 0.0893 mol

Now

we will calculate number of molecules by using following formula

          No. of moles = no. of molecules / Avogadro's number

Rearrange the above equation

            no. of molecules = No. of moles x Avogadro's number . . . . . . (3)

Where

Avogadro's number = 6.022 x 10²³

Put values in above equation 3

            no. of molecules =  0.0893 mol x 6.022 x 10²³

            no. of molecules =  5.4 x 10²²

So,

By calculation 2 L of CO₂ have 5.4 x 10²² molecules of CO₂

8 0
3 years ago
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