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boyakko [2]
3 years ago
8

How many moles of magnesium are needed to react with 3.0 mol of o2?

Chemistry
1 answer:
JulsSmile [24]3 years ago
6 0
The answer is 4.0 moles of magnesium
because...
..

...4.0mol Makmol O2 =3.0mol O2
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30 g of hydrogen reacts with 120 g of oxygen to form water.How much water is produced?
Rus_ich [418]

According to law of conservation of mass.

In a chemical reaction Mass is neither created nor destroyed.

  • Mass of product =Mass of reactant

#1

Mass of water

\\ \sf\longmapsto 30+120=150g

#2

Mass of sulphur:-

\\ \sf\longmapsto 136.9-111.6=25.3g

6 0
3 years ago
A 4 kg rock is rolling 10 m/s. Find its kinetic energy
Pavel [41]
KE = 1/2mv^2
KE = 1/2(4)*10 m/s^2
KE = 2 * 10
KE = 20 joules

Answer: 20 joules 
8 0
3 years ago
Explain how a Buffer acts to resist pH change in a system upon addition of an acid or a base
Leokris [45]

Answer:

Explanation has been given below.

Explanation:

  • A buffer consists of either of a weak acid along with it's conjugate base or a weak base along with it's conjugate acid.
  • Let's consider a buffer consists of a weak acid along with it's conjugate base
  • If we add an acid to this buffer then conjugate base gets protonated and converted to corresponding weak acid. So effect of addition of acid gets neutralized by forming weak acid rather than increase in concentration of proton in solution.
  • If we add a base to this buffer then weak acid gets converted to corresponding conjugate base. So effect of addition of base gets neutralized by forming conjugate base rather than in crease in concentration of hydroxyl ion in solution.
4 0
4 years ago
What is the mass of carbon in 290 g of CO2?
Elis [28]

Answer:

The mass of CO22 in total is 264 g.

The atomic mass for C is 12 g / mole.

The molar mass for CO22 is (12 + (2 × 16)) = 44 g / mole.

m C = (12 / 44) × 264 = 72 g

So, there are 72 g of C in 264 g of CO2

Explanation:

there's the answer have a good day.

4 0
3 years ago
what is the theoretical mass of xenon tetrafluoride that should form when 130.g of xenon is reacted with 100.g of F2? what is th
serg [7]

Answer:

The answer to your question is: 70.7 %

Explanation:

Equation

                  Xe   +   2F₂    ⇒    XeF₄

limiting reactant = Xe

Xe is the limiting reactant because the ratio is:

theoretical = 131/ 76 = 1.72 g

experimental ratio = 130/100 = 1.3  the amount of F increased.

                     131.3 g of Xe ------------------ 207 g of XeF₄

                     130 g of Xe  -------------------  x

                         x = (130 x 207) / 131.3

                        x = 205 g of XeF₄

% yield = 145 / 205 x 100

% yield = 70.7

5 0
3 years ago
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