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GenaCL600 [577]
2 years ago
10

30 g of hydrogen reacts with 120 g of oxygen to form water.How much water is produced?

Chemistry
1 answer:
Rus_ich [418]2 years ago
6 0

According to law of conservation of mass.

In a chemical reaction Mass is neither created nor destroyed.

  • Mass of product =Mass of reactant

#1

Mass of water

\\ \sf\longmapsto 30+120=150g

#2

Mass of sulphur:-

\\ \sf\longmapsto 136.9-111.6=25.3g

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Nikolay [14]

Answer:

Hey mate.......

Explanation:

This is ur answer......

<em>Metals are an excellent conductor of electricity and heat because the atoms in the metals form a matrix through which outer electrons can move freely. Instead of orbiting their respective atoms, they form a sea of electrons that surround the positive nuclei of the interacting metal ions.</em>

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8 0
3 years ago
Which pair has identical electron configurations?
Thepotemich [5.8K]

Identical electron configurations : K⁺ and Cl⁻

<h3>Further explanation  </h3>

In an atom, there are levels of energy in the shell and sub-shell  

This energy level is expressed in the form of electron configurations.  

Charging electrons in the sub-shell uses the following sequence:  

<em>1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s², 4d¹⁰, 5p⁶, 6s², etc.  </em>

  • S²⁻ and CI

S²⁻ : [Ne] 3s²3p⁶

Cl : [Ne] 3s²3p⁵

  • K⁺ and CI⁻

K⁺ : 1s² 2s² 2p⁶ 3s² 3p⁶

Cl⁻ : 1s² 2s² 2p⁶ 3s²3p⁶

  • S and Ar

S :[Ne] 3s²3p⁴

Ar : [Ne] 3s²3p⁶

  • Cl⁻ and K

Cl⁻ : 1s² 2s² 2p⁶ 3s²3p⁶

K : 1s² 2s² 2p⁶ 3s² 3p⁶4s¹

6 0
3 years ago
A method used by the U.S. Environmental Protection Agency (EPA) for determining the concentration of ozone in air is to pass the
baherus [9]

Answer: 1. 9.08\times 10^{-6} moles

2. 90 mg

Explanation:

O_3(g)+2NaI(aq)+H_2O(l) \rightarrow O_2(g)+I_2(s)+2NaOH(aq)

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus 4.54 \times 10^{-6} moles of ozone is removed by =\frac{2}{1}\times 4.54 \times 10^{-6}=9.08\times 10^{-6} moles of sodium iodide.

Thus 9.08\times 10^{-6} moles of sodium iodide are needed to remove 4.54\times 10^{-6} moles of O_3

2. \text{Number of moles of ozone}=\frac{0.01331g}{48g/mol}=0.0003moles

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus 0.0003 moles of ozone is removed by =\frac{2}{1}\times 0.0003=0.0006 moles of sodium iodide.

Mass of sodium iodide= moles\times {\text {molar mass}}=0.0006\times 150g/mol=0.09g=90mg    (1g=1000mg)

Thus 90 mg of sodium iodide are needed to remove 13.31 mg of O_3.

3 0
3 years ago
What is the starting molecule for glycolysis?
meriva
Glucose is the starting molecule for glycolysis.
5 0
3 years ago
Which is a substance that is made up of only one type of atom?
muminat

Answer:

compound

Explanation:

7 0
3 years ago
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