Options found elsewhere:
-always genetically identical to one parent
-always genetically identical to both parents
-never genetically identical to one parent
-sometimes genetically different than both parents
Answer:
-sometimes genetically different than both parents
Explanation:
Protists are eukaryotes that cannot be classed as animals, plants, or fungi. They are quite diverse. Examples include amoeba, plasmodium, and slime mould.
Because they are so diverse, protists also have very different modes of reproduction. Some protists undergo asexual reproduction, where they simply make a copy of themselves without a mate. Others undergo sexual reproduction.
Therefore, the only option that can be correct is "-sometimes genetically different than both parents" .
If they were always genetically identical to one parent or both parents, that would mean that sexual reproduction could not be possible. If they were never genetically identical to one parent, that would mean that asexual reproduction could not be taking place.
Answer:
*magnetic reversal
*magnetic minerals
*fossils
*sea-floor spreading
Explanation:
so all are right <em><u>EXCEPT </u></em> *continental drift
<span>B is the correct answer. Multicellular organisms, as with almost all organisms, begin life as a single cell. The increase in the number of cells can be as a result of cell division or cells combining together. </span>
Answer:
a. Ligase
b. Ligase (
it's repeated)
Explanation:
DNA synthesis begins, therefore, by synthesizing a short segment of RNA called a primer, which primer is synthesized by an enzyme called Primasa. Primasa is an RNA polymerase that uses DNA as a template. All fragments of Okazaki begin with a Primer. Subsequently, the DNA polymerase III Holoenzyme performs the synthesis of the corresponding DNA fragment until it reaches the next primer. At that time, DNA polymerase Ia replaces the DNA polymerase Holoenzyme III. The DNA polymerase I is responsible for removing the RNA primer through its 5'P-3'OH exonueotic activity and at the same time fills the hole by synthesizing DNA.
Finally, the two Okazaki fragments have to be joined, it is necessary to link the 3'OH end of a fragment with the 5'P of the next fragment. This work of sealing and joining the successive fragments is done by Ligase.
