Answer:A certain vehicle loses 3.5% of its value each year. If the vehicle has an initial value of $11,168, construct a model that represents the value of the vehicle after a certain number of years. Use your model to compute the value of the vehicle at the end of 6 years.
A certain vehicle loses 3.5% of its value each year. If the vehicle has an initial value of $11,168, construct a model that represents the value of the vehicle after a certain number of years. Use your model to compute the value of the vehicle at the end of 6 years.
Explanation:A certain vehicle loses 3.5% of its value each year. If the vehicle has an initial value of $11,168, construct a model that represents the value of the vehicle after a certain number of years. Use your model to compute the value of the vehicle at the end of 6 years.
Answer:
The answer to this question can be defined as follows:
Explanation:
The sky driver began his sky journey from Arkansas, drove across the Tennessee River then landed in North Carolina. He returned to both the north in the very same direction. He began with NC, traveled through Tennessee, eventually lands in Arkansas. But North Carolina has been in the third state on which skydiver was traveling over, and It's also more than 700 miles from Arkansas to the NC.
Answer:
The correct answer is: The low power objective.
Explanation:
The low power objective can cover a large field of sight which is ver useful for analyzing several specimens or to inspect smaller ones.
This power also helps the microscope to get aligned and has a reach for the low objective of 10X.
Answer:
Explanation:
Given that:
The height of a triangular stabilizing fin on its stern is 1 ft tall
and it length is 2 ft long.
Temperature = 60 °F
The objective is to determine the drag on the fin when the submarine is traveling at a speed of 2.5 ft/s.
From these information given; we can have a diagrammatic representation describing how the triangular stabilizing fin looks like as we resolve them into horizontal and vertical component.
The diagram can be found in the attached file below.
If we recall ,we know that;
Kinematic viscosity v = 
the density of water ρ = 62.36 lb /ft³
which is less than < 5.0 × 10⁵
Now; For laminar flow; the drag on the fin when the submarine is traveling at 2.5 ft/s can be determined by using the expression:
where;
= strip area
Therefore;
Let note that y = 0.5x from what we have in the diagram,
so , x = y/0.5
By applying the rule of integration on both sides, we have:
Let U = (2-2y)
-2dy = du
dy = -du/2
![F_D = -0.568 [ \dfrac{\frac{1}{2}U^{ \frac{1}{2}+1 } }{\frac{1}{2}+1}]^0__2](https://tex.z-dn.net/?f=F_D%20%3D%20-0.568%20%5B%20%5Cdfrac%7B%5Cfrac%7B1%7D%7B2%7DU%5E%7B%20%5Cfrac%7B1%7D%7B2%7D%2B1%20%7D%20%20%7D%7B%5Cfrac%7B1%7D%7B2%7D%2B1%7D%5D%5E0__2)
![F_D = -0.568 [ \dfrac{2}{3}U^{\frac{3}{2} } ] ^0__2](https://tex.z-dn.net/?f=F_D%20%3D%20-0.568%20%5B%20%5Cdfrac%7B2%7D%7B3%7DU%5E%7B%5Cfrac%7B3%7D%7B2%7D%20%7D%20%20%20%5D%20%5E0__2)
![F_D = -0.568 [0 - \dfrac{2}{3}(2)^{\frac{3}{2} } ]](https://tex.z-dn.net/?f=F_D%20%3D%20-0.568%20%5B0%20-%20%20%5Cdfrac%7B2%7D%7B3%7D%282%29%5E%7B%5Cfrac%7B3%7D%7B2%7D%20%7D%20%20%20%5D)
![F_D = -0.568 [- \dfrac{2}{3} (2.828427125)} ]](https://tex.z-dn.net/?f=F_D%20%3D%20-0.568%20%5B-%20%5Cdfrac%7B2%7D%7B3%7D%20%282.828427125%29%7D%20%20%20%5D)
