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3 years ago

Thermal conductivity of AISI 316 Stainless Steel at 90ºC is 14.54 W/m K. Convert this value to IP system.

Engineering

1 answer:

abruzzese [7]3 years ago

7 0

Answer:

the value of conductivity in IP is $8.406\dfrac{Btu}{ft.hr.F}$

Explanation:

Given that

Thermal conductivity K=14.54 W/m.K

This above given conductivity is in SI unit.

SI unit IP unit Conversion factor

m ft 0.3048

W Btu/hr 0.293

The unit of conductivity in IP is Btu./ft.hr.F.

Now convert into IP divided by 1.73 factor.

$0.57\dfrac{Btu}{ft.hr.F}=1 \dfrac{W}{m.K}$

$0.57\times 14.54\dfrac{Btu}{ft.hr.F}=14.54 \dfrac{W}{m.K}$

$8.406\dfrac{Btu}{ft.hr.F}=14.54 \dfrac{W}{m.K}$

So the value of conductivity in IP is $8.406\dfrac{Btu}{ft.hr.F}$

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