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3 years ago

Thermal conductivity of AISI 316 Stainless Steel at 90ºC is 14.54 W/m K. Convert this value to IP system.

Engineering

1 answer:

abruzzese [7]3 years ago

7 0

Answer:

the value of conductivity in IP is $8.406\dfrac{Btu}{ft.hr.F}$

Explanation:

Given that

Thermal conductivity K=14.54 W/m.K

This above given conductivity is in SI unit.

SI unit IP unit Conversion factor

m ft 0.3048

W Btu/hr 0.293

The unit of conductivity in IP is Btu./ft.hr.F.

Now convert into IP divided by 1.73 factor.

$0.57\dfrac{Btu}{ft.hr.F}=1 \dfrac{W}{m.K}$

$0.57\times 14.54\dfrac{Btu}{ft.hr.F}=14.54 \dfrac{W}{m.K}$

$8.406\dfrac{Btu}{ft.hr.F}=14.54 \dfrac{W}{m.K}$

So the value of conductivity in IP is $8.406\dfrac{Btu}{ft.hr.F}$

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2 years ago

A furnace wall composed of 200 mm, of fire brick. 120 mm common brick 50mm 80% magnesia and 3mm of steel plate on the outside. I

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common brick to magnesia = 1218 °C - (3/70)(4643.7) = 1019 °C

magnesia to steel = 1019 °C -0.2(4643.7) = 90.06 °C

_____

<em>Comment on temperatures</em>

Most temperatures are rounded to the nearest degree. We wanted to show the small temperature drop across the steel plate, so we showed the inside boundary temperature to enough digits to give the idea of the magnitude of that.

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