Question

Thermal conductivity of AISI 316 Stainless Steel at 90ºC is 14.54 W/m K. Convert this value to IP system.

Answer 1

Answer:

the value of conductivity in IP is $8.406\dfrac{Btu}{ft.hr.F}$

Explanation:

Given that

Thermal conductivity K=14.54 W/m.K

This above given conductivity is in SI unit.

     SI unit                                           IP unit              Conversion factor

    m                                                      ft                      0.3048

   W                                                       Btu/hr               0.293          

 

The unit of conductivity in IP is Btu./ft.hr.F.

Now convert into IP divided by 1.73 factor.

$0.57\dfrac{Btu}{ft.hr.F}=1 \dfrac{W}{m.K}$

So

$0.57\times 14.54\dfrac{Btu}{ft.hr.F}=14.54 \dfrac{W}{m.K}$

$8.406\dfrac{Btu}{ft.hr.F}=14.54 \dfrac{W}{m.K}$

So the value of conductivity in IP is $8.406\dfrac{Btu}{ft.hr.F}$