Answer:
64%
Step-by-step explanation:
divide 80 by 125 and get .64
Z=1 eventually you get 15 divided by 15 giving you Z=1 it’s a long equation
<u>the correct question is</u>
The denarius was a unit of currency in ancient rome. Suppose it costs the roman government 10 denarii per day to support 4 legionaries and 4 archers. It only costs 5 denarii per day to support 2 legionaries and 2 archers. Use a system of linear equations in two variables. Can we solve for a unique cost for each soldier?
Let
x-------> the cost to support a legionary per day
y-------> the cost to support an archer per day
we know that
4x+4y=10 ---------> equation 1
2x+2y=5 ---------> equation 2
If you multiply equation 1 by 2
2*(2x+2y)=2*5-----------> 4x+4y=10
so
equation 1 and equation 2 are the same
The system has infinite solutions-------> Is a consistent dependent system
therefore
<u>the answer is</u>
We cannot solve for a unique cost for each soldier, because there are infinite solutions.
Answer:
(g - f)(x) = 3x - 33
Step-by-step explanation:
Arrange f(x)= 2x + 13 and g(x) = 5x -20 vertically as shown below:
g(x) = 5x - 20
-f(x) = -2x - 13
----------------------
(g - f)(x) = 3x - 33
A^2 + 31 = 155 - I squared each of b and c for those numbers
a^2 = 155 - 31
a^2 = 124
a = 4 * sqrt(31)