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DIA [1.3K]
3 years ago
12

A 79.7 kg base runner begins his slide into second base while moving at a speed of 4.77 m/s. The coefficient of friction between

his clothes and Earth is 0.635. He slides so that his speed is zero just as he reaches the base. The acceleration of gravity is 9.8 m/s 2 . What is the magnitude of the mechanical energy lost due to friction acting on the runner? Answer in units of J.
Physics
1 answer:
SashulF [63]3 years ago
6 0

To solve this problem we will apply the concept related to the kinetic energy theorem. Said theorem states that the work done by the net force (sum of all forces) applied to a particle is equal to the change experienced by the kinetic energy of that particle. This is:

\Delta W = \Delta KE

\Delta W = \frac{1}{2} mv^2

Here,

m = mass

v = Velocity

Our values are given as,

m = 79.7kg

v = 4.77m/s

Replacing,

\Delta W = \frac{1}{2} (79.7kg)(4.77m/s)^2

\Delta W = 907J

Therefore the mechanical energy lost due to friction acting on the runner is 907J

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Katena32 [7]

KE= 1/2 mv^2

Kinetic Energy is equal to 1/2 x mass x velocity squared

The mass of the larger ball has TWICE
the kinetic energy. KE is directly proportional to the mass.

6 0
3 years ago
Air "breaks down" when the electric field strength reaches 3 × 106 n/c, causing a spark. A parallel-plate capacitor is made from
Lera25 [3.4K]

Electric field between the plates of parallel plate capacitor is given as

E = \frac{Q}{A\epsilon_0}

here area of plates of capacitor is given as

A = 0.055 * 0.055

A = 3.025 * 10^{-3}

also the maximum field strength is given as

E = 3 * 10^6 N/C

now we will plug in all data to find the maximum possible charge on capacitor plates

3 * 10^6 = \frac{Q}{3.025 * 10^{-3}*8.85 * 10^{-12}}

Q = 8.03 * 10^{-8} C

so the maximum charge that plate will hold will be given by above

3 0
3 years ago
Read 2 more answers
A tow truck is pulling 25,000 kg van with a tow hook that meets the van at an angle of 30° with the ground. How much force must
Law Incorporation [45]

Answer:

86605.08 N

Explanation:

The equation to calculate the force is:

Force = mass * acceleration

The force and the acceleration does not have the same direction in this case, so we need to decompose the force into its horizontal component, which is the force that will generate the horizontal acceleration:

Force_x = Force * cos(30)

Then, we have that:

Force_x = mass * acceleration

Force * cos(30) = 25000 * 3

Force * 0.866 = 75000

Force = 75000 / 0.866 = 86605.08 N

3 0
3 years ago
A drop
exis [7]

Answer:

27.5\  m

Explanation:

As we know that volume of cylinder is

v=\pi r^{2} *h

Where v=volume , h= height or thickness and r= radius

Here,

v= 10 m ,\  diameter= 10, \ r=\frac{diameter}{2} \ r=\frac{10}{2}\\ r=5

Putting these values in the previous equation , we get

10\ = \frac{22}{7} *5 *5*h\\ 14\ =\ 110*h\\h=\frac{110}{14} \\h=\frac{55}{2} \\\\h=27.5\  m

Therefore thickness is 27.5 m

7 0
3 years ago
If two equal charges are separated by a certain distance, the force of repulsion is F. Given F1, if each charge in F1 is doubled
Alisiya [41]

Answer:F_2=16\times F_1

Explanation:

Given

Force of repulsion between two charge particle is given by force F

Electrostatic force is given by

F=\frac{kq_1q_2}{r^2}

where q_1 and q_2 is the charges  of particle

r=distance between charge particle

=\frac{kq^2}{r^2}when charges are doubled and distance is reduced to half

i.e. q become 2 q and r becomes 0.5 r

F_2=\frac{k(2q)^2}{(0.5r)^2}

F_2=\frac{kq^2}{r^2}\times 4\times 4

F_2=16\times F_1

         

6 0
3 years ago
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