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nata0808 [166]
3 years ago
6

If 230 W of power is produced in 10 seconds, how much work is done?

Physics
2 answers:
liq [111]3 years ago
7 0

Answer:

Hello There!!

Explanation:

Use this equation:Work done = Force x Distance.

Work done=230W×10s

Work done=2300J

hope this helps,have a great day!!

~Pinky~

skad [1K]3 years ago
4 0

\huge{\textbf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}} {\color{pink}{:}}}}}

Work done = force × distance

work done = 230W×10s

work done = 2300J

  • Thanks
  • hope it helps.
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velocity of 66 km/hr.

Explanation:

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A girl throws a ball of mass 0.80 kg against a wall. The ball strikes the wall horizontally with a speed of 25 m/s, and it bounc
erma4kov [3.2K]

Answer:

F = 800N

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Explanation:

Applying the impulse-momentum equation;

Impulse = change in momentum

Ft = m∆v

F = (m∆v)/t

Where;

F = force

t = time

m = mass

∆v = v2 - v1 = change in velocity

Given;

m = 0.80 kg

t = 0.050 s

The ball strikes the wall horizontally with a speed of 25 m/s, and it bounces back with this same speed.

v2 = 25 m/s

v1 = -25 m/s

∆v = v2 - v1 = 25 - (-25) m/s = 25 +25 = 50 m/s

Substituting the values;

F = (m∆v)/t

F = (0.80×50)/0.05

F = 800N

the magnitude of the average force exerted on the wall by the ball is 800N

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3 years ago
What is the acceleration of a proton moving with a speed of 7.7 m/s at right angles to a magnetic field of 1.9 T
iris [78.8K]

Answer:

The acceleration of the proton is 1.403 x 10⁹ m/s²

Explanation:

Given;

speed of proton, v = 7.7 m/s

magnitude of magnetic field, B = 1.9 T

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F = qvBsinθ

Centripetal force on the moving proton is given by;

F = m(\frac{v^2}{r})\\\\F = m(a_c) \\\\a_c \ is \ the \ centripetal \ acceleration

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ac = \frac{(1.602*10^{-19})(7.7)(1.9)sin(90)}{1.67*10^{-27}}\\\\a_c = 1.403*10^{9} \ m/s^2

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What is the critical angle and how does it relate to total internal reflection?
liubo4ka [24]

Answer:

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