Can someone help on this one

Physics

1 answer:

beks73 [17]3 years ago

4 0

An action-reaction pair shows the direct relationship two objects have <u>directly</u> on each other. Therefore, the correct answer is C. The Moons gravity pulls on you, and your gravity pulls on the Moon because it is moon gravity-person person gravity-moon.

Choice A would be made correct if it was you pull on a drawer and the drawer pushes on you OR the table pushes on the ground and the ground pushes on the table.

Choice B would be made correct if it was a computer sits on a table and the table pushes up on the computer.

Choice D would be made correct if it was an eraser sits on a shelf and the shelf pushes up on the eraser OR the wall pushes on the shelf and the shelf pushes against the wall.

Hope this helps!!

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A 5,400 W motor is used to do work. If the motor is used for 640 s, about how much work could it do?

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Answer:

3,500,000 J

Explanation:

WORK = POWER * TIME

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The outer layer of cable on a cable reel is 16.2 cm from the center of the reel. The reel is initially stationary and can rotate

ahrayia [7]

Answer:

B. w=12.68rad/s

C. α=3.52rad/s^2

Explanation:

We can solve this problem by taking into account that (as in the uniformly accelerated motion)

$\theta=\omega_{0}t+\frac{1}{2}\alpha t^{2}\\\theta = \frac{s}{r}$ ( 1 )

where w0 is the initial angular speed, α is the angular acceleration, s is the arc length and r is the radius.

In this case s=3.7m, r=16.2cm=0.162m, t=3.6s and w0=0. Hence, by using the equations (1) we have

$\theta=\frac{3.7m}{0.162m}=22.83rad$

$22.83rad=\frac{1}{2}\alpha (3.6s)^2\\\\\alpha=2\frac{(22.83rad)}{3.6^2s}=3.52\frac{rad}{s^2}$

to calculate the angular speed w we can use $\alpha=\frac{\omega _{f}-\omega _{i}}{t _{f}-t _{i}}\\\\\omega_{f}=\alpha t_{f}=(3.52\frac{rad}{s^2})(3.6)=12.68\frac{rad}{s}$