Answer:
<em>The cyclist is traveling at 130 m/s</em>
Explanation:
<u>Constant Acceleration Motion
</u>
It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.
Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:
The cyclist initially travels at 10 /s and it's accelerating at a=6m/s^2. We need to know the new speed when t= 20 seconds have passed.
Apply the above equation:
The cyclist is traveling at 130 m/s
Answer:
Explanation:
Let hotter star has surface area of A . The cooler star would have surface area 9 times that of hotter star ie 9A , because its radius is 3 times hot star. Let temperature of hot star be T ₁.
Total radiant energy is same for both the star
Using Stefan's formula of black body radiation,
For cold star E = 9A x σ T⁴
For hot star E = A x σ T₁⁴
A x σ T₁⁴ = 9A x σ T⁴
T₁⁴ = (√3)⁴T⁴
T₁ = √3T .
b )
Let the peak intensity wavelength be λ₁ and λ₂ for cold and hot star .
As per wein's law
for cold star , λ₁ T = b ( constant )
for hot star λ₂ √3T = b
dividing
λ₁ T / λ₂ √3T = 1
λ₂ / λ₁ = 1 / √3
ANSWER:
Angular displacement is analogous to distance.
Angular velocity is analogous to velocity.
EXPLANATION:
FOR ANGULAR DISPLACEMENT AND DISTANCE
Angular displacement = theta
theta = s/r
s = linear dispalcement/distance
r= radius.
so ,
linear displacement/distance s = theta * r.
FOR ANGULAR VELOCITY AND VELOCITY
Angular velocity = w
w = v/r
v = velocity
r = radius
so,
velocity v = w * r.
Answer:
acceleration will be tripled.
Explanation:
We know, when an object is performing Simple harmonic motion, the force
experience by it is directly proportional to its displacement from its mean position.
Also, F = ma , therefore, acceleration is also proportional to its displacement .
Now, F = kx
Therefore, 
If we triple the displacement i.e, 3x.
Acceleration 
Therefore, acceleration is also tripled.
Hence, this is the required solution.
