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2 years ago

Can someone help on this one

Physics

1 answer:

beks73 [17]2 years ago

4 0

An action-reaction pair shows the direct relationship two objects have <u>directly</u> on each other. Therefore, the correct answer is C. The Moons gravity pulls on you, and your gravity pulls on the Moon because it is moon gravity-person person gravity-moon.

Choice A would be made correct if it was you pull on a drawer and the drawer pushes on you OR the table pushes on the ground and the ground pushes on the table.

Choice B would be made correct if it was a computer sits on a table and the table pushes up on the computer.

Choice D would be made correct if it was an eraser sits on a shelf and the shelf pushes up on the eraser OR the wall pushes on the shelf and the shelf pushes against the wall.

Hope this helps!!

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katrin2010 [14]

Time period of any moon of Jupiter is given by

$T = 2\pi \sqrt{\frac{r^3}{GM}}$

from above formula we can say that mass of Jupiter is given by

$M = \frac{4 \pi^2 r^3}{GT^2}$

now for part a)

$r = 4.22 * 10^8 m$

T = 1.77 day = 152928 seconds

now by above formula

$M = \frac{4 \pi^2 r^3}{GT^2}$

$M = \frac{4 \pi^2 (4.22 * 10^8)^3}{(6.67 * 10^{-11})(152928)^2}$

$M = 1.9* 10^{27} kg$

Part B)

$r = 6.71 * 10^8 m$

T = 3.55 day = 306720 seconds

now by above formula

$M = \frac{4 \pi^2 r^3}{GT^2}$

$M = \frac{4 \pi^2 (6.71 * 10^8)^3}{(6.67 * 10^{-11})(306720)^2}$

$M = 1.9* 10^{27} kg$

Part c)

$r = 10.7 * 10^8 m$

T = 7.16 day = 618624 seconds

now by above formula

$M = \frac{4 \pi^2 r^3}{GT^2}$

$M = \frac{4 \pi^2 (10.7 * 10^8)^3}{(6.67 * 10^{-11})(618624)^2}$

$M = 1.89* 10^{27} kg$

PART D)

$r = 18.8 * 10^8 m$

T = 16.7 day = 1442880 seconds

now by above formula

$M = \frac{4 \pi^2 r^3}{GT^2}$

$M = \frac{4 \pi^2 (18.8 * 10^8)^3}{(6.67 * 10^{-11})(1442880)^2}$

$M = 1.889* 10^{27} kg$

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Answer:

1/2 Hz

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A simple harmonic motion has an equation in the form of

$x(t) = Acos(\omega t - \phi)$

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Since our body has an equation of x = 5cos(π t + π/3) we can equate $\omega = \pi$ and solve for frequency f

$2\pi f = \pi$

f = 1/2 Hz

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