3 years ago

Sin^2x + sin^2x + cos²x

Mathematics

1 answer:

Nezavi [6.7K]3 years ago

7 0

Answer:

Answer:

A. 2 sinx cosx - 1 + 2 sin^2 x.

Step-by-step explanation:

sin2x = 2 sinx cosx

cos2x = cos^2x - sin^2x

So sin2x - cos2x = 2 sinx cosx - ( cos^2x - sin^2x)

But cos^2 x = 1 - sin^2 x, so we have:

2 sinx cosx - (1 - sin^2 x - sin^2x)

= 2 sinx cosx - 1 + 2 sin^2 x.

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3 years ago

Read 2 more answers

1) y+3+ Z/4+z use y=-5, and z = 4<br>

elena-14-01-66 [18.8K]

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4 years ago

Bloody ell someone help me

vodomira [7]

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4 years ago

Two thirds of a number is no more than -10

Aliun [14]

Let x be the number in the problem. When it states that x is "no more than -10", it means than it is less than or equal to -10. So, we have

$\frac{2}{3}$ x≤-10

In order to cancel out the $\frac{2}{3}$ on the left and isolate x, we multiply both sides by $\frac{3}{2}$ (since $\frac{3}{2}$ · $\frac{2}{3}$ =1). Thus, we have

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Therefore, x≤-15

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3 years ago