Question

A rigid tank contains air at a pressure of 70 psia and a temperature of 55 ˚F. By how much will the pressure increase as the temperature is increased to 115 ˚F?

Answer 1

Answer:

P_2 = 62.69 psi

Explanation:

given,

P₁ = 70 psia               T₁ = 55° F    = (55 + 459.67) R

P₂ = ?                         T₂ = 115° F    = (115 + 459.67) R

we know,

p = ρ RT

ρ is the density which is constant

R is also constant

now,

$\dfrac{P_2}{P_1} =\dfrac{T_2}{T_1}$

$\dfrac{P_2}{70} =\dfrac{55+459.67}{115+459.67}$

    P_2 = 62.69 psi

Hence, the increase in Pressure is equal to P_2 = 62.69 psi