Explanation:
Effective nuclear charge is defined as he net positive charge experienced by an electron in an atom. It is termed "effective" because the shielding effect of electrons prevents higher orbital electrons from experiencing the full nuclear charge of the nucleus due to the repelling effect of inner-layer electrons.
The 1s is the closest shell to the nucleus of an therefore maximum nuclear charge is experienced. The formula for effective nuclear charge is:
Zeff = Z – S
where
Z = the number of protons in the nucleus, and
S = the shielding constant, the average number of electrons between the nucleus and the electron.
Hence, the energy required to remove an electron from the 1s orbital is the strongest.
W = F x d/x = (m x Ag) x h, therefore, mass (2kg x 9.8) x 2.5m = 49J
Answer:
C sedimentary rocks is the answer.
Explanation:
Answer:
Displacement = 
Magnitude of displacement = 13.89 units
Angle of displacement = 30.26°
Explanation:
Mark the co-ordinates of each of the end points of the vectors.
The marked co-ordinates are shown below.
Displacement is the shortest distance between two points. Here, displacement between the starting and end points is the vector
.
Displacement vector for a point A
from origin O is given as:

Magnitude is given as:

Direction of the vector is given as:

Therefore, displacement vector is:

Magnitude of displacement is given as:

Angle of displacement is:

°
Answer:
Length of the arc of this sector, l = 14 cm
Explanation:
It is given that, the perimeter of a sector of a circle is the sum of the two sides formed by the radii and the length of the included arc.
Perimeter of sector, P = 28 cm
Area of sector, 
According to figure,
2r + l = 28 ............(1)
Area of sector, 
Where,
is in radian and 
Since, 


Put the value of r in equation (1) so,


On solving above equation for l we get, l = 14 cm. So, the length of the arc of this sector is 14 cm. Hence, this is the required solution.