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VladimirAG [237]
4 years ago
8

What is the velocity of a first-order reaction when the reactant concentration is 6 x 10-2M and the rate constant is 8 x 103sec-

1?
A) 1.33 x 105M-1•sec-1

B) 1.33 x 105M•sec

C) 7.5 x 10-2M•sec

D) 4.8 x 102M•sec-1

E) not enough data are given to make this calculation
Chemistry
1 answer:
tresset_1 [31]4 years ago
5 0

Answer:

D) 4.8 × 10² M/s

Explanation:

Let's consider the following generic reaction.

A → B

The rate law is:

v = k . [A]ⁿ

where,

v: velocity

k: rate constant

[A]: concentration of the reactant A

n: reaction order for A

<em>What is the velocity of a first-order reaction when the reactant concentration is 6 × 10⁻²M and the rate constant is 8 × 10³s⁻¹?</em>

v = k . [A]¹ = 8 x 10³s⁻¹ . 6 x 10⁻²M = 4.8 × 10² M/s

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An 8 oz serving of whole milk has 8.0 g of fat, 8.0 g of protein, and 13 g of carbohydrates. Approximately how many kilocalories
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<h3>Answer:</h3>

156 calories

<h3>Explanation:</h3>
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1 g of carbohydrate = 4 calories

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3 years ago
How many moles of lithium chloride will be formed by the reaction of chloride with 4.28 mol of lithium bromide in the following
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Answer:

The answer is 4.28 moles

Explanation:

This is super easy okay, you won't forget this!

Basically mole ratios, we're just looking at the coefficients in front of the compounds, multiplying them, and dividing them as we see fit.

In this example, you can see how you need 2 moles of lithium bromide (LiBr) for the reaction, and 2 moles of lithium chloride (LiCl) will be produced.

Basically, the <u>molar ratio</u> is when you divide numbers and see how much of this do I have for that (if that makes sense).

So if you were to divide the 2 moles of LiBr / 2 moles of LiCl = 1. So we know that the mole ratio for LiBr to LiCl is 1:1 or 2:2, either or, it's the same thing.

SO THE BIG IDEA, if we have 4.28 moles of lithium bromide reacting, we should also have 4.28 moles of lithium chloride produced, BECAUSE the <u>mole ratio</u> is 1:1.

I hope this makes sense please tell me if it doesn't, I will try my best to explain a little more.

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