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VladimirAG [237]
3 years ago
8

What is the velocity of a first-order reaction when the reactant concentration is 6 x 10-2M and the rate constant is 8 x 103sec-

1?
A) 1.33 x 105M-1•sec-1

B) 1.33 x 105M•sec

C) 7.5 x 10-2M•sec

D) 4.8 x 102M•sec-1

E) not enough data are given to make this calculation
Chemistry
1 answer:
tresset_1 [31]3 years ago
5 0

Answer:

D) 4.8 × 10² M/s

Explanation:

Let's consider the following generic reaction.

A → B

The rate law is:

v = k . [A]ⁿ

where,

v: velocity

k: rate constant

[A]: concentration of the reactant A

n: reaction order for A

<em>What is the velocity of a first-order reaction when the reactant concentration is 6 × 10⁻²M and the rate constant is 8 × 10³s⁻¹?</em>

v = k . [A]¹ = 8 x 10³s⁻¹ . 6 x 10⁻²M = 4.8 × 10² M/s

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When solid carbon reacts with oxygen gas to produce carbon dioxide gas. the deltaH (enthalpy change ) value is negative .DeltaH would be on the product side of the equation.

<h3>What is enthalpy change? </h3>

In a thermodynamic system, energy is measured by enthalpy. Enthalpy is a measure of a system's overall heat content and is equal to the system's internal energy plus the sum of its volume and pressure.

Knowing whether q is endothermic or exothermic allows one to characterise the relationship between q and H. An endothermic reaction is one that absorbs heat and demonstrates that heat from the environment is used in the reaction, hence q>0 (positive). For the aforementioned equation, under constant pressure and temperature, if q is positive, then H will also be positive. In a similar manner, heat is transferred to the environment when it is released during an exothermic reaction. Thus, q=0 (negative). Therefore, if q is negative, H will also be negative.

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