Question

If the operation ⊕ is defined by p⊕q = square root of p^2 +q^2, What is 8⊕6? Please Explain

Answer 1

8⊕6 is 10

Step-by-step explanation:

We will use the substitution method to solve this problem

∵ The operation ⊕ is defined by p⊕q = $\sqrt{p^{2}+q^{2}}$

∵ You want to find 8⊕6

- Then do these steps:

• Substitute p by 8
• Substitute q by 6
• Calculate the square root of 8² + 6²

∵ p = 8

∴ p² = 8² = 64

∵ q = 6

∴ q² = 6² = 36

∵ p⊕q = $\sqrt{p^{2}+q^{2}}$

- Substitute p by 8 and q by 6 in the rule above

∴ 8⊕6 = $\sqrt{(8)^{2}+(6)^{2}}$

- Substitute 8² by 64 and 6² by 36

∴ 8⊕6 = $\sqrt{64+36}$

∴ 8⊕6 = $\sqrt{100}$

∵ $\sqrt{100}=10$

∴ 8⊕6 = 10

8⊕6 is 10

Learn more:

You can learn more about the substitution method in brainly.com/question/9390381

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