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lina2011 [118]
4 years ago
5

How many valence electrons does boron have

Physics
2 answers:
mel-nik [20]4 years ago
6 0
The correct answer is 2
marshall27 [118]4 years ago
4 0

Answer: 3

Explanation:

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Tom kicks a soccer ball on a flat, level field giving it an initial speed of 20 m/s at an angle of 35 degrees above the horizont
SVEN [57.7K]

Answer:

(a) 2.34 s

(b) 6.71 m

(c) 38.35 m

(d) 20 m/s

Explanation:

u = 20 m/s, theta = 35 degree

(a) The formula for the time of flight is given by

T = \frac{2 u Sin\theta }{g}

T = \frac{2 \times 20 \times Sin35 }{9.8}

T = 2.34 second

(b) The formula for the maximum height is given by

H = \frac{u^{2} \times Sin^{2}\theta }{2g}

H = \frac{20^{2} \times Sin^{2}35 }{2 \times 9.8}

H  = 6.71 m

(c) The formula for the range is given by

R = \frac{u^{2} \times Sin 2\theta }{g}

R = \frac{20^{2} \times Sin 2 \times 35}{9.8}

R = 38.35 m

(d) It hits with the same speed at the initial speed.

8 0
3 years ago
Isabella drops a pen off her balcony by accident while celebrating the successful completion of a physics problem.
Studentka2010 [4]

Answer:

2 seconds

Explanation:

v = at + v₀

19.62 m/s = (9.81 m/s²) t + 0 m/s

t = 2 s

6 0
3 years ago
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Question 14 of 25
natali 33 [55]

the answer is sueist

Explanation:

7 0
3 years ago
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You have a small piece of iron at 75 °C and place it into a large container of water at 25 °C. Which of these best explains what
svp [43]
D. Heat energy will be transferred within the system and if left long enough, there will be enough transferred energy to make both of them the same temperature.
3 0
3 years ago
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As an intern with an engineering firm, you are asked to measure the moment of inertia of a large wheel, for rotation about an ax
AysviL [449]

Answer:

I=2.766\ kg.m^2

Explanation:

We have:

diameter of the wheel, d=0.88\ m

weight of the wheel, w_w=280\ N

mass of hanging object to the wheel, m_o=6.32\ kg

speed of the hanging mass after the descend, v_o=4\ m.s^{-1}

height of descend, h=2.5\ m

(a)

moment of inertia of wheel about its central axis:

I=\frac{1}{2} m.r^2

I=\frac{1}{2} \frac{w_w}{g}.r^2

I=\frac{1}{2} \times \frac{280}{9.8}\times 0.44^2

I=2.766\ kg.m^2

3 0
4 years ago
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