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2 years ago

Difference between metals and nonmetals

1 answer:

5 0

Answer: Metals refers to the natural elements that are hard, shiny, opaque and dense. Non-metals implies those chemical substances that are soft, non-shiny, transparent and brittle. Most metals are hard, except sodium. Most non-metals are soft, except diamond.

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Calcular la energía cinética de un cometa cuya masa es de 5×10 elevado a 31 kg y se mueve con velocidad de 216000km/h

PolarNik [594]

The kinetic energy is $9\cdot 10^{40}J$ .

Explanation:

The kinetic energy of an object is given by

$K=\frac{1}{2}mv^2$

where

K is the kinetic energy of the object

m is the mass of the object

v is the speed of the object

For the comet in this problem, we have:

$m=5\cdot 10^{31} kg$ is its mass

$v=216,000 km/h$ is the speed

First, we convert the speed from km/h to m/s:

$v=216,000 \frac{km}{h} \cdot \frac{1000 m/km}{3600 s/h}=60,000 m/s$

Therefore, the kinetic energy of the comet is

$K=\frac{1}{2}(5\cdot 10^{31})(60,000)^2=9\cdot 10^{40}J$

Learn more about kinetic energy here:

brainly.com/question/6536722

#LearnwithBrainly

5 0

3 years ago

A piano string having a mass per unit length of 5.00 g/m is under a tension of 1350 N. Determine the speed of transverse waves i

padilas [110]

Answer:

The speed of transverse waves in this string is 519.61 m/s.

Explanation:

Given that,

Mass per unit length = 5.00 g/m

Tension = 1350 N

We need to calculate the speed of transverse waves in this string

Using formula of speed of the transverse waves

$v=\sqrt{\dfrac{T}{\mu}}$

Where, $\mu$ = mass per unit length

T = tension

Put the value into the formula

$v = \sqrt{\dfrac{1350}{5.00\times10^{-3}}}$

$v =519.61\ m/s$

Hence, The speed of transverse waves in this string is 519.61 m/s.

6 0

3 years ago

Two neutron stars are separated by a distance of 1.0 x 1012 m. They each have a mass of 1.0 x 1028 kg and a radius of 1.0 x 103

son4ous [18]

To develop this problem it is necessary to apply the concepts related to Gravitational Potential Energy.

Gravitational potential energy can be defined as

$PE = -\frac{GMm}{R}$

As M=m, then

$PE = -\frac{Gm^2}{R}$

Where,

m = Mass

G =Gravitational Universal Constant

R = Distance /Radius

PART A) As half its initial value is u'=2u, then

$U = -\frac{2Gm^2}{R}$

$dU = -\frac{2Gm^2}{R}$

$dKE = -dU$

Therefore replacing we have that,

$\frac{1}{2}mv^2 =\frac{Gm^2}{2R}$

Re-arrange to find v,

$v= \sqrt{\frac{Gm}{R}}$

$v = \sqrt{\frac{6.67*10^{-11}*1*10^{28}}{1*10^{12}}}$

$v = 816.7m/s$

Therefore the velocity when the separation has decreased to one-half its initial value is 816m/s

PART B) With a final separation distance of 2r, we have that

$2r = 2*10^3m$

Therefore

$dU = Gm^2(\frac{1}{R}-\frac{1}{2r})$

$v = \sqrt{Gm(\frac{1}{2r}-\frac{1}{R})}$

$v = \sqrt{6.67*10^{-11}*10^{28}(\frac{1}{2*10^3}-\frac{1}{10^{12}})}$

$v = 1.83*10^7m/s$

Therefore the velocity when they are about to collide is $1.83*10^7m/s$

7 0

3 years ago

What is pitch related to?

Jlenok [28]

Pitch is related to frequency

7 0

3 years ago

Real springs have mass. How will the true period andfrequency

Ad libitum [116K]

Explanation:

An perfect mass less spring, attached at one end and with a free mass attached at the other end, will have a distinct frequency of oscillation depending on its constant spring and mass. On the other hand, a spring with mass along its length will not have a characteristic frequency of oscillation.

Alternatively, based on its spring constant and mass per length, it will now have a wave Speed. It would be possible to use all wavelengths and frequencies, as long as the component fλ= S, where S is the spring wave size. If that sounds like longitudinal waves, like solid sound waves.

4 0

3 years ago

Difference between metals and nonmetals​

Difference between metals and nonmetals