The solution for this problem is:torque1 = torque2 = FL / 2
Torque 3 = Torque 4 = FL / 2 * sin (theta)
Torque 5 = 2 FL
Torque 6 = 0
So the order of the torques from smallest to largest is torque 6, (torque 3 and 4), (torque 1 and 2), torque 5.
Remember or just take note that sin (theta) < 1 is why 3 and 4 are less than 1 and 2.
Answer:
v=u+at
24=0+at
24=a×6
a=4m/s
hence
s=ut+at^2÷2
s=36m
Explanation:
since the car is brought to rest the u=0
the answer is D, deciding what will be funded and what will be cut.
