Question

Si + 2Cl2 + SiC14

Answer 1

59.43 grams of SiCl4 is formed when 10.0 grams of Si and 60.0

grams of Cl2 react.

Explanation:

Data given:

mass of Si = 10 grams

mass of chlorine gas = 60 grams

molar mass of Si = 28 grams/mole

molar mass of chlorine gas = 70.9 grams/mole

molar mass of Si$Cl_{4}$  = 169.8 grams/mole

Balanced equation:

Si + 2$Cl_{2}$ ⇒ Si$Cl_{4}$

moles of Si = $\frac{mass}{atomic mass of 1 mole}$

moles of Si = $\frac{10}{28}$

moles of Si =0.35 moles

moles of chlorine gas = $\frac{60}{70.9}$

moles of chlorine gas = 0.84 moles

from the balance reaction,

1 mole of Si gives 1 mole of Silicon tetrachloride

0.35 moles of Si will give 0.35 moles of silicon tetrachloride

mass = atomic mass x number of moles

mass = 169.8 x 0.35

mass = 59.43 grams

2 moles of chlorine gas gives 1 mole of silicon tetrachloride

0.84 moles of chlorine will give

0.84 x 2 moles= 1.68 moles of silicon tetrachloride

mass = 1.68 x 169.8

        = 285.26 grams

Mass of silicon tetrachloride fromed is 59.43 grams as silicon is the limiting reagent.