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klasskru [66]
3 years ago
12

Which of the following is a variable property for a gas ? Select all that apply.

Chemistry
2 answers:
disa [49]3 years ago
8 0
C) volume
.........
The volume of gas depends on e.g. temperature and pressure.
Molodets [167]3 years ago
4 0

The correct answer is volume and shape.

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Please help me!!!!!!
Norma-Jean [14]

Answer:

17.8ml-15.6ml is 2.2 ml then convert to cm so 2.2cm^3

4 0
2 years ago
What is the term for a solid that has been dissolved into a liquid?
Nat2105 [25]
The answer is Solute.  The solution is the whole thing.  The solvent is the major component (the liquid doing the dissolving).
6 0
3 years ago
How many moles contain 1.25x 10^15 molecules carbon dioxide?
IRISSAK [1]
Avagadros number states that 1 mol of any substance is made of 6.022 x 10²³ units.
These units could be atoms that make up an element or molecules that make up a compound. CO₂ is a compound therefore its made of CO₂ molecules.
1 mol of CO₂ contains 6.022 x 10²³ molecules of CO₂
Therefore if  6.022 x 10²³ molecules of CO₂ make up 1 mol 
then 1.25 x 10¹⁵ molecules of CO₂ make up - \frac{1.25 x 10¹⁵}{6.022 x 10²³}
Number of CO₂ moles present - 2.0756 x 10⁻⁹ mol of CO₂
7 0
3 years ago
A sample of 5.30 mLmL of diethylether (C2H5OC2H5;density=0.7134g/mL)(C2H5OC2H5;density=0.7134g/mL) is introduced into a 6.50 L L
lilavasa [31]

Answer:

1.16atm

Explanation:

We are going to derive the mass of ether from density

mass=density *volume

Also moles=mass/molecular mass

molar mass C2H5OC2H5 =74.12 g/mole

the density of ether is 0.7134 g/ml

mass C2H5OC2H5 = 5.30 ml x 0.7134 g/ml = 3.78 g

moles C2H5OC2H5 =3.78 g x 1 mole/74.12 g = 0.0509 moles

PV = nRT where P=?; n=0.0509 moles; V=6.50L; R=0.0821 Latm/Kmol; T=35ºC +273 = 308K

P = nRT/V = 0.0509)(0.0821)(308)/6.50

P = 0.198 atm (to 3 significant figures (this is the partial pressure of diethyl ether).  

TOTAL PRESSURE

P1+p2+p3

= 0.198 atm + 0.750 atm + 0.207 atm =1.1550atm

1.16atm(3 significant figures)

5 0
3 years ago
A solution is prepared by adding 27.00 mL of 2.19 M MgCl2 to enough water to make 122.00 mL. What is the Cl- concentration of 40
xeze [42]

Answer:

<em>3.88x10⁻²</em>

Explanation:

First, the amount of moles initially in the volume of the concentrated MgCl2 solution is determined:

1000 mL solution ____ 2.19 moles of MgCl₂

27.00 mL solution _____ X = 5.91x10⁻² mol of MgCl₂

<em>Calculation:</em> 27.00 mL x 2.19 moles / 1000 mL = 0.05913 moles ≡ 5.91x10⁻² mol of MgCl₂

This is the amount of moles of MgCl₂ in both the initial and the diluted solution, since only water was added to the first solution, therefore, in 122.00 mL of the new solution, there are 5.91x10⁻² mol of MgCl₂. Now it is necessary to calculate the amount of moles in 40 mL of the new solution prepared:

122.00 mL of solution _____ 5.91x10⁻² mol of MgCl₂

40.00 mL of solution ____ X = 1.94x10⁻² of MgCl₂

<em>Calculation:</em> 40.00 mL x 5.91x10⁻² mol / 122.00 mL = 0.01939 moles ≡ 1.94x10⁻² MgCl₂

Now, when the MgCl₂ compound is in an aqueous solution, it dissociates into the ions that form it as follows:

MgCl₂ ⇒ Mg⁺² (aq) + 2 Cl⁻ (aq)

Therefore, for each mole of MgCl₂ that dissolves in water, it will dissociate producing two moles of Cl⁻ chloride ion. Mathematically:

1 mole of MgCl₂ ____ 2 moles of Cl⁻

1.94x10⁻² moles of MgCl₂ _____ X = 3.88x10⁻² moles of Cl⁻

<em>Calculation:</em> 1.94x10⁻² moles x 2 moles / 1 mole = 0.03877 ≡ 3.88x10⁻² moles of Cl⁻

Therefore, <em>in 40.00 mL of the new solution, there will be a concentration of 3.88x10⁻² moles of Cl⁻</em>

8 0
3 years ago
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