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elena-14-01-66 [18.8K]
3 years ago
6

You are planning on making punch and you would like to cool it with ice. At the store, there are 2 different one-pound bags of i

ce to choose from: one that contains large ice cubes one that contains small ice chips. You only want to purchase one bag of ice and will add the entire bag to the punch. Would one of the bags cool the punch at a faster rate? If so, which one and why? If not, why? Would one of the bags of ice cool the punch to a lower temperature? If so, which one and why? If not, why? (Not really a chem q, I didn't know what subject to put it in)
Chemistry
1 answer:
zaharov [31]3 years ago
4 0
The answer to this equation is 72 because 69+3=72 so therefore it’s 72
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What Is This Item Called?
eduard
It looks like something to screw onto something and manage the flow of... I'd say... knob for a screw
4 0
4 years ago
The complete combustion of propane (C3H8) in the presence of oxygen yields CO2 and H2O: C3H8 (g) + 5O2 (g) 3CO2 (g) + 4H2O (g) a
mixas84 [53]

Answer:

26.9 L is the volume of CO₂, we obtained

Explanation:

The reaction is: C₃H₈(g) + 5O₂(g)  →  3CO₂ (g) + 4H₂O (g)

Let's determine the reactants moles:

27.5 g . 1mol / 44 g = 0.625 moles

We need density of O₂ to determine mass and then, the moles.

O₂ density = O₂ mass / O₂ volume

O₂ density . O₂ volume = O₂ mass

1.429 g/L . 45L = O₂ mass → 64.3 g

Moles of O₂ → 64.3 g . 1mol/32g = 2.009 moles

Let's find out the limiting reactant:

1 mol of propane needs 5 moles of oxygen to react

Then, 0.625 moles will react with (0.625 . 5)/1 = 3.125 moles of O₂

Oxygen is the limiting reactant, we need 3.125 moles but we only have 2.009 moles

Ratio is 5:3. 5 moles of O₂ produce 3 moles of CO₂

Therefore, 2.009 moles of O₂ must produce (2.009 .3) /5 = 1.21 moles of CO₂. Let's find out the volume, by Ideal Gases Law (STP are 1 atm and 273K, the standard conditions)

1 atm . V = 1.21 moles . 0.082 . 273K

V = (1.21 moles . 0.082 . 273K) / 1atm = 26.9 L

3 0
3 years ago
Analysis of an unknown sample indicated the sample contained 0.140 grams of N and 0.320 grams of O. The molecular mass of the co
vlada-n [284]

Answer:

the molecular formula of the compound is N2O4

Explanation:

- Find the empirical formula

mole of N present = mass of N divided by molar mass of N = 0.140/14 = 0.01 mole

mole of O present = mass of O divided by molar mass of O = 0.320/16 = 0.02 mole

Divide both by the smallest number of mole to determine the coefficient of each, the smallest number of mole is 0.01 thus:

quantity of N = 0.01/0.01 = 1

quantity of O = 0.02/0.01= 2

thus the empirical formula = NO2

- Now determine the molecular formula by finding the ratio of molecular formula and empirical formula

Molar mass of molecular formula = 92.02 amu = 92.02 g/mole

Molar mass of empirical formula NO2 = (14 + (16 x 2)) = 46 g/mole

the x factor = 92.02/46 = 2

Molecular formula = 2 x NO2 = N2O4

5 0
4 years ago
What is the mass of a cube of aluminum that is 4.0 cm on each edge? The density of aluminum is 2.7 g/cm3.
Y_Kistochka [10]
Mass will be 172.8 gram only
7 0
3 years ago
What is 198g=____kg please help me
Marat540 [252]

Answer:

0.198kg

Explanation:

because,

1kg = 1000g

so

198g = 0.198g

divide it by 1000 to get kg

5 0
3 years ago
Read 2 more answers
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