3 years ago

Factor the following expression 27y3 -343

1 answer:

4 0

27y^3 -343 starts out with 27y^3, and 343 is the cube of 7. Thus, we know immediately that 27y3 -343 is the diffeence of two squares.

The appropriate rule is a^3 - b^3 = (a - b)(a^2 + ab + b^2).

Here, we have 27y3 -343 = (3y - 7)(9y^2 + 12y + 49)

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Citrus2011 [14]

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jok3333 [9.3K]

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bazaltina [42]

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<u>Step-by-step explanation:</u>

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