<span>C</span>⁰<span> H</span>₃⁺¹<span> C</span>⁰<span> O</span>⁻²<span> O</span>⁻²<span> H</span>⁺¹
C is 0
H = + 1
O = - 2
Answer:
The change in enthaply when 10.0 g of nitrogen triiodide decomposes is -3.67 kJ.
Explanation:

Enthalpy of the reaction when 2 moles of nitrogen triiodide decomposed =

Enthalpy of the reaction when 1 moles of nitrogen triiodide decomposed :

Mass of nitrogen triiodide decomposed = 10.0 g
Moles of nitrogen triiodide = 
Change in enthaply when 0.02532 moles of nitrogen triiodide decomposed:

First, write out a complete balanced reaction for the combustion of ethane, ethane + O2 -> CO2 + H20. Then, divide the grams of ethane by its Molar Mass and multiply by 32, the molar mass of O2.
Answer:

Explanation:
Equation for the heterogeneous system is given as:
⇄

The concentrations and pressures at equilibrium are:
![[A] = 9.68*10^{-2}M](https://tex.z-dn.net/?f=%5BA%5D%20%3D%209.68%2A10%5E%7B-2%7DM)

![[C]=14.64M](https://tex.z-dn.net/?f=%5BC%5D%3D14.64M)
![[D]=10.11M](https://tex.z-dn.net/?f=%5BD%5D%3D10.11M)

If we convert both pressure into bar; we have:



1 torr = 0.001333 bar

![K=\frac{[P_E]^3}{[A]^2[P_B]^3}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BP_E%5D%5E3%7D%7B%5BA%5D%5E2%5BP_B%5D%5E3%7D)

